Same as handshake problem.
Each of n persons plays against n-1 persons for a total of n(n-1)/2 games.
The division by 2 is necessary to avoid double counting the game A vs B and B vs A.
For n=8, then number of games played in the first round is 8(8-1)/2=28 games.
Answer:
The graph is below to help you, hopefully this does helps:)
* Mark me the brainliest:)!!
Answer:
1.575
Step-by-step explanation:
Answer:A hope this helped