Note: The missing diagram is attached below for a reference.
Answer:
Step-by-step explanation:
Given:
- ∠T and ∠V are right angles.
-
║ 
To Prove:
- Δ
≅ Δ
As
∠ 
≅ ∠ 
≅ 
(Given)
Side 
≅
║ 
and is a transverse
So,
∠ 
≅ ∠ 
![\left[alternate\:\:interior\:\:angles\right]](https://tex.z-dn.net/?f=%5Cleft%5Balternate%5C%3A%5C%3Ainterior%5C%3A%5C%3Aangles%5Cright%5D)
Thus,
- Δ ≅ Δ
Keywords: proof, paragraph, logic, reason
Learn more about proof and reason from brainly.com/question/13396866
#learnwithBrainly
Area= 50.24 or 50.2 rounded to the nearest tenth
If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.
the sqrt525^7 = 3359983566.19
So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.
(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)
X = (15 - 8y)/9
-5[(15 - 8y)/9] + 12y = -107
(-75/9) + (40/9) + 12y = -107
y = -8.59
x = [15 - 8(-8.59)]/9
x = 9.3
(x,y) = (9.3, -8.59)
All multiples of 10 end in a zero besides the number zero. So 10, 20, 30 and so on....
case.
