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ale4655 [162]
3 years ago
15

8 4/5 - 2/3 - ___ = 3 1/10

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

x= 5 1/30

Step-by-step explanation:

hope this is fine :)

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Find the explicit formula for a 1 =-4,a n =a n-1 +9,n>=2
Mrrafil [7]

Given:

a_1=-4 and a_n=a_{n-1}+9 where n\geq 2.

To find:

The explicit formula for the given recursive formula.

Solution:

We know that recursive formula of an AP is:

a_n=a_{n-1}+d

Where, d is the common difference.

We have,

a_n=a_{n-1}+9

Here, d=9.

The first term of the AP is a_1=-4.

The explicit formula for an AP is:

a_n=a_1+(n-1)d

Substituting a_1=-4 and d=9, we get

a_n=-4+(n-1)9

a_n=-4+9n-9

a_n=-13+9n

Therefore, the required explicit formula for the given sequence is a_n=-13+9n.

6 0
3 years ago
Help please!?!?!?!?!?!?!?!?!
Tpy6a [65]

Answer:

Your answer is D.

Step-by-step explanation:

If you need explanation ask me in comment

5 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
At a concession stand, a pickle and two bags of chips costs a total of $3.25. Three pickles and four bags of chips costs a total
kolbaska11 [484]

Answer:

A bag of chips costs $1

A pickle costs $1.25

Step-by-step explanation:

P + 2c = 3.25                            Start with these two equations

3p + 4c = 7.25

p = -2c + 3.25                           Solve for one variable

3(-2c +3.25) + 4c = 7.25           Substitute

-6c + 9.75 + 4c = 7.25

-2c = -2

c = 1

p + 2(1) = 3.25                           Substitute

p + 2 = 3.25

p = 1.25

4 0
3 years ago
Determine which system will produce indefinite many solutions
Vinvika [58]

Answer:

Where are the systems?

Step-by-step explanation:

5 0
3 years ago
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