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ale4655 [162]
3 years ago
15

8 4/5 - 2/3 - ___ = 3 1/10

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

x= 5 1/30

Step-by-step explanation:

hope this is fine :)

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Charla wants to determine the vertex of the function f(x) = x2 – 18x + 60 by changing the function into vertex form. Which state
7nadin3 [17]

Answer:

A. the x-coordinate of the vertex is greater than the y-coordinate.

Step-by-step explanation:

hope this helps

correct me if this is wrong

6 0
3 years ago
I NEED IT NOW!!! I ALSO NEED YOUR WORK OF HOW YOU GET YOUR ANSWER !! THANK YOU!
Mars2501 [29]

Answer:

Solve the rational equation by combining expressions and isolating the variable

x

.

All real numbers

Interval Notation:

−∞,∞)

Step-by-step explanation:

3 0
3 years ago
What is the median for the set of data shown below?<br> 16, 23, 24, 39, 45, 78, 95
iris [78.8K]

Answer:

39

Step-by-step explanation:

The median is the middle number

16, 23, 24, 39, 45, 78, 95

There are 7 numbers so the middle number is the 4th number

6, 23, 24,    39    , 45, 78, 95

The median is 39

8 0
3 years ago
Read 2 more answers
Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem
hammer [34]

Answer:

a) A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) ||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

Step-by-step explanation:

a) considering the equation:

Minimize x_{1}^{2}  +2x_{2}x^{2}  +3x_{3}^{2}+(x_{1}   -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}

A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right] (matrix A)

vector b

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) If Pxn is matrix B and p-vector d, we have:

minimize (-6x_{2}+4)^{2}  +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}

Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]

\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]

Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1  \\x_{1}+8x_{2}-3  \end{array}\right] =1

||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) minimize 2(-bx_{2}+4)^{2}  +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2}  +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2}  -\sqrt{3})^{2}  +(2x_{1} -16x_{2} -6)^{2}

in matrix:

A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

6 0
3 years ago
What's 5384 multiply by 65
Slav-nsk [51]
349960 because you multiply and stuff

5 0
3 years ago
Read 2 more answers
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