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ale4655 [162]
3 years ago
15

8 4/5 - 2/3 - ___ = 3 1/10

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

x= 5 1/30

Step-by-step explanation:

hope this is fine :)

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<h2>\large\mathfrak{{\pmb{\underline{\red{Given}}{\red{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles
  • ∠RSU = (4x – 15)°
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<h2>\large\mathfrak{{\pmb{\underline{\color{red}{To~find}}{\color{red}{:}}}}}</h2>
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<h2>\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles

\sf\implies{ \angle RSU + \angle USV = 90 \degree }

\sf\implies{ (4x-15) + 20 = 90 }

\sf\implies{ 4x-15+20=90}

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\sf\implies{4x=90-5}

\sf\implies{4x=85}

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\sf\implies{ {\orange{\underline{\boxed{\sf{\pmb{x=21.25}}}}}}}

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5 0
3 years ago
Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "<br>f (x) over g (x)​
kondor19780726 [428]

Answer:

\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}

Step-by-step explanation:

The first function is f(x)=9x^3+21x^2-14

The second function is g(x)=3x+1.

\frac{f(x)}{g(x)}=\frac{9x^3+21x^2-14}{3x+1}

We perform the long division as shown in the attachment to obtain the quotient as: Q(x)=3x^2+6x-2 and remainder R=-12.

Therefore:

\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}

where x\ne -\frac{1}{3}

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4 years ago
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Answer:

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you have to first multiply them

-140

since it has to be an aditive inverse you write the opposite

140

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