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3 years ago

HELP HELP HELP HELPPPPPP

Mathematics

2 answers:

kompoz [17]3 years ago

4 0

Answer:

uhuuivfb igeg

Step-by-step explanation:

c chbqufuivphw

nignag [31]3 years ago

3 0

Danggg how much help you need?

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Please answer i need help

r-ruslan [8.4K]

Answer:

$\huge\boxed{\text{B) 1}}$

Step-by-step explanation:

In order to find which expression is equivalent to $(8^5 \times 3^{-7})^0$ , we need to note the order of operations.

PEMDAS tells us that when solving an equation, we'd go in this order.

Parentheses

Exponents

Multiplication/Division

Addition/Subtraction

Using this, we'd start by evaluating what's inside the parentheses, $8^5 \times 3^{-7}$ . We'd then bring that value to the 0th power.

Wait... there's something special about bringing anything to the 0th power. Bringing anything to the 0th power makes the value 1.

It can be -5... it can be 1,000,000, any number possible, taken to the 0th power, will always be 1.

So no matter what the value inside the parentheses is, taking it to the 0th power will always make it 1.

Therefore, this expression is equivalent to 1.

Hope this helped!

8 0

3 years ago

Which of the following points is collinear with (1,1) and (2,2)?

katen-ka-za [31]

collinear points lies in a single line

that means sum of distance between 2 points is equal to distance between end points.

for example if A B and C lies in a line then

AB + BC = AC

here (1,1) , (2,2) and (3, 3) follows the same rule. ao ans is option D

8 0

3 years ago

A store manager instructs some new trainees that a leather chair priced at 200$ winds up costing A customer $218 once the sales

Ulleksa [173]

Answer:

9.00%

Step-by-step explanation:

So, we would do

18 divided by 200 = 9.00%

Therefore your answer will be 9.00%

Hope this helps!

5 0

3 years ago

A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 2004-01

ZanzabumX [31]

The complete problem is as following:
A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 5 times as long to go from Centre to Millwood as it does to go from Elm to Centre. The entire trip is 48 miles. How far is the ride from Centre to Millwood? Name a geometric postulate or theorem used to find the solution.
A) 8 miles ; segment addition postulate
B) 8 miles; segment bisector theorem
C) 40 miles; segment addition postulate
D) 40 miles; segment bisector theorem
=======================================================
Solution ;
Let the time taken from Elm to Centre = x ⇒⇒⇒ segment (1)

∴ the time taken from Centre to Millwood = 5x ⇒⇒⇒ segment (2)

∴ Total time of all the trip = x + 5x = 6x
The entire trip is 48 miles and the train traveling with constant speed
∴ speed = distance over the time = $\frac{48}{6x} = \frac{8}{x}$
So, the distance from Centre to Millwood = speed * time = $\frac{8}{x} * 5x = \framebox{40 \ miles}$
As seen in the answer, we have added the segment (1) to segment (2)
So, The geometric postulate used to find the solution is segment addition postulate

So, the correct option is C) 40 miles; segment addition postulate

=======================================================
Another solution :
From Elm to Centre = x ⇒⇒⇒ segment (1)
From Centre to Millwood = 5x ⇒⇒⇒ segment (2)
∵ The train traveling with constant speed
∴ Distance is proportional with the time
By using the ratio and proportional as following

$Segment (1) : segment (2) : Total \\ \ \ 
. \ \ \ \ \ \ \ x \ \ \ \ \ \ : \ \ \ \ \ 5x \ \ \ \ \ \ \ : \ \ 6x \\
. \ \ \ \ \ \ \ ? \ \ \ \ \ \ : \ \ \ \ \ \ \ ? \ \ \ \ \ \ \ \ : \ \ \ 48$

∴ segment (2) = $\frac{48 * 5x}{6x} = \framebox {40 miles}
$

we have used the postulate of segment addition to add x and 5x.

So, the correct option is C) 40 miles; segment addition postulate

4 0

4 years ago

A university's freshman class has 1000 students. 600 of those students are majoring in Engineering. What percentage of the fresh

velikii [3]

Answer:60%

Step-by-step explanation:

If there are 1000 students in total and 600 are majoring in engineering, you divide 600 by 1000 to find the percent of students majoring in engineering. (600/1000) =.6

To turn a decimal into a percent you move the decimal over 2 places making it 60%.

3 0

4 years ago

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