Answer:
Area: 6a^2
Perimeter: 12a^2
Step-by-step explanation:
To find the area of a triangle, use the formula A=1/2 b*h. The base is 3a^2 and the height is 4a^2.
A= 1/2 (3a^2)(4a^2)
A = 1/2 (12a^4)
A = 6a^4
To find the perimeter of the triangle, add each of the sides of the triangle. The third side, the hypotenuse, can be found using Pythagorean theorem.
Now add each of the sides: 3a^2 + 4a^2 +5a^2 = 12a^2
18.03 inches
Put the dimensions into the pythagorean theorem, that will give you the answer.
Answer is a hope it helps
<u><em>Answer:</em></u>
SAS
<u><em>Explanation:</em></u>
<u>Before solving the problem, let's define each of the given theorems:</u>
<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle
<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle
<u>Now, let's check the given triangles:</u>
We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
This means that the two triangles are congruent by <u>SAS</u> theorem
Hope this helps :)
