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arlik [135]
3 years ago
12

Find the value of X. What is x and how do you solve for y first.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

id.k but i hope this wuote helps u have a great day :) :)

Step-by-step explanation:

Everything will be okay in the end. If it’s not okay, it’s not the end

Have a nice day :) :) :)

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mash [69]

1. is 1/12. 2. is 1 3/7

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3 years ago
Sebastian bought a 30-pack of mechanical pencils and plans to give the same number of pencils each to 6 friends.
Korolek [52]

Answer: 5 pack

Step-by-step explanation:

From the question, we are informed that Sebastian bought a 30-pack of mechanical pencils and plans to give his friends an equal number of pencils to the 6 friends.

Therefore, each friend will get:

= 30 / 6

= 5 packs

4 0
3 years ago
Read 2 more answers
Need help with part c
Artyom0805 [142]
First understand that this is a linear graph. Find 2 points on the graph. We can use (0,1) and (3,-3).

Look at how much the x increases, in this case the x value increases by 0+3, so 3.

Then see how much the y value increases (make sure to evaluate them in the same order) 1 + (-3) = -2.

So you know that the y value decreases by 2 units for every 3 unit increase in x. Therefore the slope is y=(-2/3)x

Then figure out what you add to the end. The y intercept is (0,1), so add 1 to the end of y=(-2/3)x to move it up.

Your resulting eq is y=(-2/3)x+1
8 0
3 years ago
Sweet t purchased a new pair of jeans to wear at the battle of the bands on sale at 40% off. he saved 20$ what is the original p
kodGreya [7K]
0.40X = 20

X = 20/0.40 = $50
7 0
3 years ago
If a triangle has sides 4, 6 and 10 and a 2nd similar triangle has a perimeter of 60, find the 2nd largest side of the 2nd trian
algol13
The first triangle has a perimeter of 4+6+10 = 20.

The 2nd longest side is 6/20 = 3/10 of the perimeter. In the larger triangle, the 2nd longest side will have length (3/10)*60 = 18.


_____
These side lengths mean the "triangle" is a line segment. That is, it has zero area.
8 0
3 years ago
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