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AveGali [126]
2 years ago
6

What’s ur opinion on that manga rate it out of 10

Mathematics
1 answer:
Fiesta28 [93]2 years ago
5 0
2/10 quit reading it after 1 minute
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150 is 25% of what number? Four students solved this problem using equivalent ratios. Choose the student whose work is correct.​
jenyasd209 [6]

Answer:

liam's answer is correct

Step-by-step explanation:

6 0
3 years ago
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The table below shows the population of a town over x years. A 2-column table with 5 rows. The first column is labeled years wit
mel-nik [20]

Answer:

10,346.0(1.1)^x

112,096 people

Step-by-step explanation:

edg

8 0
3 years ago
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Pls help!
Ludmilka [50]

Answer:

A)200%

B)I dont know sorry

C) 57.14. Not sure tho

Hope they are correct

6 0
3 years ago
Checking my work. which one?
Genrish500 [490]

Answer:

Dividing exponents you subtract.

3^8/3^5 = 3^3

3^3

Multiplying exponents when an exponent is raised to another.

(3^3)^3 = <u>3^9</u>

<h2>Final Answer is 3^{9}</h2><h2 />

Apparently this makes no sense according to comments, if you want a more indepth look into exponents search "The properties of exponents".

6 0
3 years ago
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Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
3 years ago
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