Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
it is -1
Step-by-step explanation:
2= 410x+14⇒4x+8=10x+14 ⇒6x=−6 ⇒x=−1
Answer:
Step-by-step explanation:
First one is C+1.25=2.50
2. 5V=30
3. X-44
I hope this helped.