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Elden [556K]
3 years ago
14

A car rental agency advertised renting a car for $ 23.95 per day and $ 0.32 per mile. If Trevor rents this car for 3 ​days, how

many whole miles can he drive on a $ 250 ​budget?
Mathematics
2 answers:
Crank3 years ago
5 0
Lets m is the number of miles 

23.95(3) + 0.32m = 250
71.85 + 0.32m = 250
0.32m = 250 - 71.85
0.32m = 178.15
m = 178.15  /  0.32
m = 556.71

answer: <span>Trevor can drive 556 whole miles on a $250 budget</span>
AVprozaik [17]3 years ago
4 0
Y=mx +b plug that in , so the 23.95 would be the flat fee then you add 0.32 
       250 =23.95+0.32 subtract from both sides then divide the answer is  10 miles
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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
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Answer:

A)  3%

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<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

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If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

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\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

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