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Veronika [31]
3 years ago
13

Find the sum 12x^2+9x^2

Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0
Let's simplify step-by-step.
<span><span>12<span>x^2</span></span>+<span>9<span>x^2
</span></span></span>Combine Like Terms:
<span>=<span><span>12<span>x^2</span></span>+<span>9<span>x^2
</span></span></span></span><span>=<span>(<span><span>12<span>x^2</span></span>+<span>9<span>x^2</span></span></span>)
</span></span><span>=<span>21<span>x^<span>2</span></span></span></span>
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A bag of flour weighs 5 lb. 5/7 lb of flour was used to make bread. How many
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Answer:

Step-by-step explanation:

5/1 - 5/7

35/7 - 5/7

= 30/7 = 4 2/7 lb

Multiply the denominators, 7 by 5,and 1 by 7. When you have the same denominator in each fraction you can subtract. (7x4= 28, 30-28= 2)

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Step-by-step explanation:

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Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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