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3 years ago

15

If there are no other changes, explain what effect reducing the mass of the car will have on its acceleration when starting to m

ove.

1 answer:

densk [106]3 years ago

3 0

Answer:

when the mass of an object is decreased, the acceleration will increase

when mass is increased, acceleration decreases

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The unit of work is a derived unit prove that<br>

schepotkina [342]

Answer:

88

Explanation:

because I know the answer.

7 0

3 years ago

Calculating Velocity

m_a_m_a [10]

The average velocity of the object represented by the distance time graph is $0.1\:meter\:per\:second$

The velocity of an object is the change in the distance moved by an object with time.

This could also be related to the rate of change or slope of the graph.

Average velocity = $\frac{change\:in\:distance}{change\:in\:time}$

Average velocity = $\frac{(5-0)}{(50-0}) = \frac{5}{50}=0.1\:meter\:per\:second$

Therefore, the average velocity of the object is $0.1\:meter\:per\:second$

Learn more :brainly.com/question/1378025

5 0

3 years ago

Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much power is generated by the fal

quester [9]

Answer:

5.88×10⁸ W

Explanation:

Power = energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

7 0

3 years ago

A spring on a horizontal surface can be stretched and held 0.2 m from its equilibrium position with a force of 16 N. a. How much

nekit [7.7K]

Answer:

a $W_{3.5} = 490 \ J$

b $W_{2.5} = 250 \ J$

Explanation:

Generally the force constant is mathematically represented as

$k = \frac{F}{x}$

substituting values given in the question

=> $k = \frac{16}{0.2}$

=> $k = 80 \ N /m$

Generally the workdone in stretching the spring 3.5 m is mathematically represented as

$W_{3.5} = \frac{1}{2} * k * (3.5)^2$

=> $W_{3.5} = \frac{1}{2} * 80 * (3.5)^2$

=> $W_{3.5} = 490 \ J$

Generally the workdone in compressing the spring 2.5 m is mathematically represented as

$W_{2.5} = \frac{1}{2} * k * (2.5)^2$

=> $W_{2.5} = \frac{1}{2} * 80 * (2.5)^2$

=> $W_{2.5} = 250 \ J$

5 0

3 years ago

A 61 kg zebra is traveling 8 m/s east. What is the zebra’s momentum?

klemol [59]

Momentum = Mass × Velocity
   = 61 × 8
   = 488 kg m/s east
   = 500 kg m/s east

Momentum is a vector quantity which means it has a direction as well as a numerical value (fancy word for this is magnitude). This means the final answer should also be in the direction "east".
Furthermore due to the significant figures in the question, the final answer should also be given to 1 sig fig (500) but if you don't want to then I imagine 488 is acceptable. (It's like this because we don't know how accurate we can be with the final answer from the numbers in the question.)

4 0

3 years ago