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FrozenT [24]
3 years ago
13

Spaceship A moves at 0.800 in the positive - direction, while spaceship B moves in the opposite direction at 0.750 (both speeds

are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B?
Physics
1 answer:
Eva8 [605]3 years ago
4 0

Explanation:

Spaceship A moves at 0.800 in the positive – direction, while spaceship B moves in the opposite direction at 0.750 (both speeds are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B

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A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart. What is the magnitude of the electric field betw
olya-2409 [2.1K]

Answer:

2500 N/C

Explanation:

Electric Field: This can be defined as the the force per unit charge in an electric field. The S.I unit is N/C

V = E.r ....................... Equation 1

Where V = Electric potential, E = Electric Field, r = Distance between the two parallel plate,

Make E the subject of the equation,

E = V/r .................... Equation 2

Given: V = 10 V, r = 4.00 mm = (4/1000) m = 0.004 m.

Substitute into equation 2

E = 10/0.004

E = 2500 N/C

Hence the electric field = 2500 N/C

6 0
3 years ago
Read 2 more answers
How is 'one standard kilogram' defined in SI system?<br>​
____ [38]

Explanation:

<h2>The standard one kilogram mass is the mass of platinum-iridium cylinder kept at 0 degree Celsius at the International Bureau of Weights and Measures in France. The mass is equal to mass of 1 litre of water at 4 degree Celsius.</h2>
3 0
3 years ago
If a construction worker drops a wrench from the top of a building 450 feet high the wrench will be s(t) = −16t 2 + 450 feet abo
creativ13 [48]

Answer:

-64ft/s

Explanation:

Given:

s(t)=-16t^2+450

Unknown:

\frac{ds}{dt}=v(t)=-32t

For t = 2:

v(2)=-32\times 2=-64

6 0
2 years ago
You are designing a ski jump ramp for the next Winter Olympics. You need to calculate the vertical height from the starting gate
natita [175]

Answer:

44.6 m

Explanation:

From the law of conservation of energy, the total energy at the top of the ramp, E equals the total energy at the bottom of the ramp.

E = E'

U₁ + K₁ + W₁ = U₂ + K₂ + W₂ where U₁ = potential energy at top of ramp = mgh where = height of ramp, K₁ = kinetic energy at top of ramp = 1/2mv₁² where v₁ = speed at top of ramp = 1.8 m/s, W₁ = work done by friction and air resistance at top of ramp = 0 J, U₂ = potential energy at bottom of ramp = 0 J(since the skier is at ground level h = 0), K₂ = kinetic energy at bottom of ramp = 1/2mv₂² where v₂ = speed at bottom of ramp = 28.0 m/s, W₁ = work done by friction and air resistance at bottom of ramp = 3500 J

Substituting the values of the variables into the equation, we have

U₁ + K₁ + W₁ = U₂ + K₂ + W₂

mgh + 1/2mv₁² + W₁ = U₂ + 1/2mv₂² + W₂

mgh + 1/2m(1.8 m/s)² + 0 J = 0 J + 1/2m(28 m/s)² + 3500 J

9.8 m/s² × 75 kg h + 1/2 × 75 kg (3.24 m²/s²) + 0 J = 0 J + 1/2 × 75 kg (784 m²/s²) + 3500 J

(735 kgm/s²)h + 75  kg(1.62 m²/s²) = 75 kg(392m²/s²) + 3500 J

(735 kgm/s²)h + 121.5  kgm²/s² = 29400 kgm²/s² + 3500 J

(735 kgm/s²)h + 121.5 J = 29400 J + 3500 J

(735 kgm/s²)h + 121.5 J = 32900 J

(735 kgm/s²)h = 32900 J - 121.5 J

(735 kgm/s²)h = 32778.5 J

h = 32778.5 J/735 kgm/s²

h = 44.6 m

So, the maximum height of the ramp for which the maximum safe speed will not be exceeded is 44.6 m.

4 0
2 years ago
If you are driving 100 km/h along a straight road and you look to the side for 1.6 s , how far do you travel during this inatten
denis23 [38]

Answer:

The distance traveled is 44.45 m

Solution:

As per the question:

Average speed, \bar{v} = 100\ km/h

Time, t = 1.6 s

Now, convert the average speed into m/s:

1 km = 1000 m

1 h = 60\times 60 = 3600\ s

To calculate the distance traveled:

Now,

100\ km/h = \frac{100\times 1000}{3600} = 27.78\ m/s

We know that:

Speed, \bar{v} = \frac{distance,\ d}{time,\ t}

Thus

d = \bar{v}t

d = 27.78\times 1.6 = 44.45\ m

8 0
3 years ago
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