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FrozenT [24]
3 years ago
13

Spaceship A moves at 0.800 in the positive - direction, while spaceship B moves in the opposite direction at 0.750 (both speeds

are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B?
Physics
1 answer:
Eva8 [605]3 years ago
4 0

Explanation:

Spaceship A moves at 0.800 in the positive – direction, while spaceship B moves in the opposite direction at 0.750 (both speeds are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B

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A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di
dimulka [17.4K]
=1244 and that's from my math book
7 0
3 years ago
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other
Umnica [9.8K]
The answer is c. +2.0 µC

To calculate this, we will use Coulomb's Law:

F = k*Q1*Q2/r²

where F is force, k is constant, Q is a charge, r is a distance between charges.

k = 9.0 × 10⁹  N*m/C²


It is given:

F = 7.2 N

d = 0.1 m =  10⁻¹ m

Q1 = -4.0 µC = 4 * 1.0 × 10⁻⁶ = 4.0 × 10⁻⁶

Q2 = ?


Thus, let's replace this in the formula for the force:

7.2 = 9.0 × 10⁹ * 4.0 × 10⁻⁶ * Q2/(10⁻¹)²

7.2 = 9 * 4 * 10⁹⁻⁶ * Q2/10⁻¹°²

7.2 = 36 × 10³ * Q2 / 10⁻²

Multiply both sides of the equation by 10⁻²:

7.2 × 10⁻² = 36 × 10³ * Q2

⇒ Q2 = 7.2 × 10⁻² / 36 × 10³ = 7.2/36 × 10⁻²⁻³ = 0.2 × 10⁻⁵ = 2 × 10⁻⁶ 


Since µC = 1.0 × 10^-6:

Q2 = 2 * 1.0 × 10^-6 = 2 µC

5 0
3 years ago
Atoms that make up matter are held together by what force
Elenna [48]
Intermolecular forces
6 0
3 years ago
Air in the amount of 2 lbm is contained in a well-insulated, rigid vessel equipped with a stirring paddle wheel. The initial sta
vladimir1956 [14]

Explanation:

It is known that energy balance relation is as follows.

           \Delta E_{system} = E_{in} - E_{out}

Also,   W_{in} = \Delta U

so,       W_{in} = mC_{v}(T_{2} - T_{1})  

According to the ideal gas equation,

           T_{2} = T_{1} \frac{P_{2}}{P_{1}}

Putting the values into the above equation as follows.

             T_{2} = T_{1} \frac{P_{2}}{P_{1}}

                         = (520R) \frac{40psia}{30psia}

                         = 693.3 R

Now, we will convert the temperature into degree Fahrenheit as follows.

            693.3 - 458.67

          = 234.63^{o}F

From table A-2E_{a}

 C_{p} = 0.240 Btu/lbm R  and   C_{v} = 0.171 Btu/lbm

Now, we will substitute the energy balance as follows.

            W_{in} = mC_{v}(T_{2} - T_{1})  

                         = 2 lbm \times 0.171 Btu/lbm R (693.3 - 520)

                         = 59.3 Btu

Thus, we can conclude that final temperature of air is 59.3 Btu.

6 0
4 years ago
Someone please help
Vaselesa [24]

Answer:

hi there!!

Explanation:

Nickel  149 pm

Cobalt  152 pm

Calcium  194 pm

Potassium  243 pm

So Potassium is the correct answer

6 0
3 years ago
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