in a closed system three objects have the following momentum: 11 kg* m/s, -65 kg*m/s and -100 kg m/s. the objects collide and mo
1 answer:
Explanation:
The momentum of the three objects are as follow :
11 kg-m/s, -65 kg-m/s and -100 kg-m/s
Before collision, the momentum of the system is :
After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.
It would mean that, after collision, momentum of the system is equal to the initial momentum.
Hence, final momentum = -154 kg-m/s.
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a) The car’s speed just after leaving the icy portion of the road is the first part
We have s = ut +
Here s = 130 m, a = -1.2 , u = 76 mile/hr = 33.975 m/s
After 14.72 seconds cars speed is given by v =u +at
u = 33.975m/s, a = -1.2
v = 33.975-1.2*14.72 = 16.31 m/s
So velocity of car on leaving icy surface = 16.31 m/s
b) Time taken after icy surface
0 = 16.31 - 7.10*t
t = 2.23 seconds
Distance traveled during this time
Total distance traveled = 130+18.74 = 148.74 m
c) Total time taken = 14.72+2.23=16.95 seconds