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Ne4ueva [31]
4 years ago
12

in a closed system three objects have the following momentum: 11 kg* m/s, -65 kg*m/s and -100 kg m/s. the objects collide and mo

ve together. What is the total momentum after the collision? 55 kg*m/s 275 kg * m/s -55kg * m/s -275 kg m/2
Physics
1 answer:
guajiro [1.7K]4 years ago
4 0

Explanation:

The momentum of the three objects are as follow :

11 kg-m/s, -65 kg-m/s and -100 kg-m/s

Before collision, the momentum of the system is :

P_i=11+(-65)+(-100)\\\\P_i=-154\ kg-m/s

After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.

It would mean that, after collision, momentum of the system is equal to the initial momentum.

Hence, final momentum = -154 kg-m/s.

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When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted
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8 0
3 years ago
PLEASE HELP I GIVE BRAINLIEST AND 15 POINTS
deff fn [24]
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
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60
​
= 6 Kg
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F=ma
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3 0
3 years ago
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