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Travka [436]
3 years ago
12

Evaluate 2a-b for a=2 and b=3.

Mathematics
1 answer:
Masja [62]3 years ago
8 0

Answer:

1

Step-by-step explanation:

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Help me please show your work
Elenna [48]
C = 1.1b


constant = 1.1

hope it helps


7 0
3 years ago
Find A and please include explanation please. If you don’t know please don’t write whatever to get the points
PolarNik [594]

\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies  c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------


\bf \begin{cases} a=90\\ b=55\\ c=50 \end{cases}\implies cos^{-1}\left(\cfrac{b^2+c^2-a^2}{2bc}\right)=\measuredangle A \\\\\\ cos^{-1}\left(\cfrac{55^2+50^2-90^2}{2(55)(50)}\right)=\measuredangle A\implies cos^{-1}\left(\cfrac{-2575}{5500}  \right)=\measuredangle A \\\\\\ 117.91634^o\approx \measuredangle A

5 0
3 years ago
A linear sequence starts a + 2b, a + 6b, a+10b
Trava [24]

Answer:

a = -12

b = 3

Step-by-step explanation:

second term = a + 6b

to find the 5th term, notice the pattern (since this is a linear equation, each term increases by the same amount) and each term increases by 4b: 2b -> 6b -> 10b.

therefore, the 4th term would be a+14b and the 5th would be a+18b

so a + 6b = 8

and a + 18b = 44

u now have two simultaneous equations, which can be solved through substitution or elimination. I'm gonna use elimination because it's quicker in this case:

a + 6b = 8\\- (a + 18b = 44)\\ -12b = -36\\b = 3

steps: (since the a would cancel out by subtracting, subtract then solve for b. divide by -12 on both sides to isolate the b)

now that u know the value of b, substitute it into an equation to solve for a:

a + 6b = 8

a + 6(3) = 8

a + 24 = 8

a = 8 - 24

a = -16

hope this helps!

6 0
3 years ago
What is 72/5 in decimal form
horsena [70]

Answer:

14.4

Step-by-step explanation:

72/5 in decimal form equals 14.4

8 0
3 years ago
Read 2 more answers
The colonists in Texas were fighting for
Zigmanuir [339]

Answer:

Texas Revolution, also called War of Texas Independence, War fought from October 1835 to April 1836 between Mexico and Texas colonists that resulted in Texas’s independence from Mexico and the founding of the Republic of Texas (1836–45). Although the Texas Revolution was bookended by the Battles of Gonzales and San Jacinto, armed conflict and political turmoil that pitted Texians (Anglo-American settlers of the Mexican state of Coahuila and Texas) and Tejanos (Texans of mixed Mexican and Indian descent) against the forces of the Mexican government had occurred intermittently since at least 1826.

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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