All categories

3 years ago

Select all the statements that are true about rectangles.

Mathematics

1 answer:

ivolga24 [154]3 years ago

8 0

Step-by-step explanation:

Diagonals are congruent.
Diagonals bisect angles.
Diagonals are perpendicular.
Diagonals bisect each other.

You might be interested in

D. 10 + 11k can someone plzz help meeee plzzzz

torisob [31]

Answer:

(A). $\frac{15}{2}$ + $\frac{33}{4}$ <em>k</em>

Step-by-step explanation:

$\frac{3}{4}$ × 2(2 + 4k + 3 + $\frac{3}{2}$ k ) = $\frac{3}{2}$ ( 5 + $\frac{11}{2}$ k ) = $\frac{15}{2}$ + $\frac{33}{4}$ k

8 0

3 years ago

Kari's paper cup holds 6 fluid ounces. If one ounce is equivalent to 29.6 milliliters, how many milliliters does her paper cup h

Degger [83]

Answer:

Equivalent measurements: teaspoon, ounce, pint, pound

You will find a table of equivalent measurements in the back of many cookbooks:

1 tablespoon = 3 teaspoons

1 cup = 16 tablespoon = 8 ounces

1/4 cup = 4 tablespoons

1/3 cup = 5 tablespoons plus 1 teaspoon

1 pint = 2 cups = 16 ounces

1 quart = 4 cups (2 pints) = 32 ounces

1 gallon = 4 quarts

1 pound = 16 ounces

1/2 pound = 8 ounces

1/4 pound = 4 ounces

Note that a pint is 16 ounces of volume, while a pound is 16 ounces of weight. The popular rhyme "A pint's a pound, the world around" can help you remember this, but keep in mind that they're not really equivalent.

Doubling a recipe can be easy (just put in two of each measurement), but what if you need to divide a recipe in half? Here are some measurements that may help:

Measurement 1/2 Measurement

1/8 teaspoon just a dash

1 tablespoon 1 1/2 teaspoons

1/4 cup 2 tablespoons

1/3 cup 2 tablespoons + 2 teaspoons

3/4 cup 6 tablespoons

Step-by-step explanation:

7 0

3 years ago

Day one finding a weeb finish this sentence and I will give you brainiest

Hatshy [7]

Answer:

weeb -_-

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .