A ball is thrown upwards and it’s height h m,at time t s,is given by h=7t-4.9t2.How long does the ball spend more than 1.5m abov
e ground?
1 answer:
Answer: From what you wrote the I think the ball is drop
At time 0 you are 7 meters above ground
You basically just need to solve for
1.5 =7t-4.9t^2
by rearrange the equation you get
4.9t^2-7t+1.5=0
by using Quadratic Formula
t=1.166s
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