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OLga [1]
3 years ago
14

The Si base unit, the mole, is a measurement of:

Chemistry
2 answers:
melomori [17]3 years ago
3 0

Answer:

amount of substance

Explanation:

The mole is the base SI unit of amount of substance

Bond [772]3 years ago
3 0

Explanation:

The mole is a measurement of amount of substance

hope it is helpful to you

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Why do carbs and fats have the same atoms, but store different amount of energy?
cestrela7 [59]
Carbs have larger molecules
7 0
3 years ago
The industrial solvent carbon disulfide (CS2) is produced when coke (C) and sulfur dioxide (SO2) react. If 8.00 g of SO2 reacts,
NikAS [45]

Answer:

0.0624 mol

Explanation:

Trust me i know :)

7 0
2 years ago
The air pressure for a certain tire is 109 kPa. What is this pressure in atmospheres?​
Len [333]

1.08 atm is the pressure for a certain tire in atmosphere.

<u>Explanation:</u>

One kilo pascal (1 kPa) corresponds to 1000 pascal. Another common unit used for pressure is atmosphere (symbolised as ‘atm’). 1 atm refers the standard atmospheric pressures and corresponds to 760 mm Hg and 101.3 kPa. Atmospheric pressures are commonly referred as square inches (psi)/ pounds.

  1 \mathrm{atm}=101.3 \mathrm{kPa}=101,325 \mathrm{Pa}=760 \mathrm{mm} \mathrm{Hg}=760 \text { torr }=14.7 \mathrm{lb} / \mathrm{in}^{2}(\mathrm{psi})

Given:

The air pressure for a certain tire = 109 kPa

We need to find pressure in atmospheres

So, we know,

1 atm = 101.3 kPa

Hence,

\frac{109 \mathrm{kPa}}{1} \times \frac{1 \mathrm{atm}}{101.3 \mathrm{kPa}}=1.076=1.08 \mathrm{atm}

1.08 atm is the pressure for a certain tire in atmosphere.

3 0
4 years ago
A flask contains 0.370 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask
Nana76 [90]
I will have I friend answer it
4 0
4 years ago
What is the total pressure in atmospheres in a 10.0L vessel containing 2.50 x 10-3 mol H2, 1.00 x 10-3
grigory [225]

Answer:

Total pressure = 16.42× 10⁻⁹atm

Explanation:

Given data:

Moles of H₂ = 2.50 × 10⁻³ mol

Moles of He = 1.00 × 10⁻³ mol

Mass of Ne = 3 × 10⁻⁴ mol

Volume = 10 L

Temperature = 35°C

Total pressure = ?

Solution:

Pressure of hydrogen:

P = nRT / V

P = 2.50 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 63.22× 10⁻³  atm. L /10 L

P = 6.3 × 10⁻³atm

Pressure of helium:

P = nRT / V

P = 1.00 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 25.29 × 10⁻³ atm. L /10 L

P = 2.53× 10⁻³ atm

Pressure of neon:

P = nRT / V

P = 3 × 10⁻⁴ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 75.86× 10⁻³ atm. L /10 L

P = 7.59× 10⁻³ atm

Total pressure of mixture:

P(mixture)  = pressure of hydrogen + pressure of helium+ pressure of neon

P(mixture)  = 6.3 × 10⁻³atm + 2.53× 10⁻³ atm + 7.59× 10⁻³ atm

P(mixture) = 16.42× 10⁻⁹atm

8 0
3 years ago
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