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3 years ago

What forms of matter exists that are not made of chemical bonds?

Chemistry

1 answer:

zepelin [54]3 years ago

8 0

Mixtures

Explanation:

The forms of matter that exists without having chemical bonds between them are mixtures.

Mixtures are impure substances. They are made of matter that are not chemically bonded to one another.

Here are some of the characteristics of a mixture:

Composition is indefinite i.e they consist of two or more elements and or compounds in any proportion by mass
The constituents retain their identities i.e physical properties are not altered.
The constituents reacts differently to changed conditions.
They can easily be separated into constituents by physical methods.

Many natural mixtures exists and several others can be formulated. Examples include air, sea-water, muddy water, alloys e.t.c

learn more:

Mixture brainly.com/question/1446244

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What happens when a gas is heated in a closed metal container

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a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.

Alex17521 [72]

Answer:

$m_{Co}=6998g=7.0kg$

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

$Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})$

Thus, we solve for the mass of cobalt as shown below:

$m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg$

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3 years ago

Ethylene (C2H4) is the starting material for the preparation of polyethylene. Although typically made during the processing of p

Solnce55 [7]

Answer:

1.17 grams

Explanation:

Let's consider the balanced equation for the combustion of ethylene.

C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)

We can establish the following relations:

1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
The molar mass of C₂H₄ is 28.05 g/mol.

The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:

$-59.0kJ.\frac{1molC_{2}H_{4}}{-1411kJ} .\frac{28.05gC_{2}H_{4}}{1molC_{2}H_{4}} =1.17gC_{2}H_{4}$

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3 years ago

What is the volume of 5.8g of H2?

BartSMP [9]

At standard temperature and pressure, one mole of gas occupies 22.4 L. Knowing this, we must convert the grams to moles and moles to liters to get your answer. Here's how you do it!
$\frac{5.8gH2}{1} | \frac{1moleH2}{2.0gH2}| \frac{22.4LH2}{1moleH2} \\ \frac{5.8*1*22.4LH2}{2.0} \\ \frac{129.92LH2}{2.0} \\ 64.96LH2 \\ 65LH2$
With significant figures accounted for, 5.8 grams of hydrogen gas occupies 65 L.

Hope this helps!

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4 years ago