The molecules of a solid is compactly arranged. It is made up of repeating blocks called unit cells. The density of a unit cell is:
ρ = nA/VNₐ
where
n is the number of atoms per unit cell
A is the atomic weight of solid
V is the volume of unit cell
Na is Avogadro's number (6.022×10²³)
For a face-centered cubic unit cell, there are 4 atoms (n=4). The volume of the unit cell follows the formula of the cube, s³. The atomic weight of gold is 197 g. So, the solution is as follows:
ρ = (4 atoms)(197 g/mol)(1 kg/1000 g)/(407×10⁻¹² m)³(6.022×10²³ atoms/mol)
ρ = 19,408.5 kg/m³
The answer in this question is FALSE. Hydrogen atom has electronic configuration 1s^1. It needs only one more electron to make a closed sub-shell. Therefore, a stable hydrogen atom does not have an octet but a duplet. Therefore, the statement is false.
Explanation:
In order to calculate the number of moles of a compound, we will find it out as follows.
No. of moles of chromium(III) chloride =
=
= 0.63 moles
No. of moles of =
=
= 5.88 moles
No. of moles of =
=
= 1.05 moles
No. of moles of =
=
= 1.02 moles
No. of moles of KCl =
=
= 1.34 moles
No. of moles of =
=
= 1.31 moles
No. of moles of =
=
= 6.25 moles
No. of moles of =
=
= 2.27 moles
No. of moles of =
=
= 1.11 moles
Therefore, we can conclude that out of the given options contains the largest number of moles of compound.
Answer:
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Explanation: