So 28=8
35 more would be 63 so
28=8
63=x
Cross multiply and 28x=504
x=18
To find the equation of a line using two coordinate points, use the slope intercept formula, (y2-y1)/(x2-x1). Using this formula, plug in your values from the two coordinates (-5, -5) and (1, -3). This would look like this:
(-3-(-5))/(1-(-5))
When simplified, you should get 2/6 or 1/3 as your slope or m value. Now that you have your slope, now use your slope intercept equation y=mx+b and plug in your known values. Since you know the m value is 1/3 and you can use one of your set of points to plug into the x and y values, you can plug in these values and solve for b (the coordinate you use doesn't matter but I'm just using the (1,-3)). This would look like this:
-3=1/3(1)+b
When you simplify, you should get -3=1/3+b and when you subtract both sides by 1/3, you should get b=-10/3.
Now that you have your m and b values, you can conclude that your equation for the line would be y=1/3x-10/3
Answer:
640
Step-by-step explanation:
pleas check my answer
Y/3-a=b
First multiply 3 on both sides
y/3-a=b
*3 *3
---------------
y-a=3b
Now add the a on both sides
y-a=3b
+a +a
----------------
y=3b+a
Your answer is
Y=3b+a
The polar coordinates are given by M(x, y), such tha x=rcos(teta), and y=rsin(teta), it was given M(5,5), so 5=rcos(teta) and 5=rsin(teta), the ratio gives us 5/5= cotan (teta), 1= cotan (teta), implies 1= tan(teta), so teta = Pi/4, let's find r
5=rsin(Pi/4)=r . sqrt(2)/2, so r =10/sqrt(2)=10sqrt(2)
finally the polar coordinates are (r, teta) = (10sqrt(2), Pi/4)
