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4 years ago

Which planet is not an outer planet? A. Mars B. Uranus C. Neptune D. Jupiter

Chemistry

2 answers:

3241004551 [841]4 years ago

8 0

The answer to your question is MARS

m_a_m_a [10]4 years ago

3 0

Answer:

D C E A

Explanation:

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How can we think differently about maintaining social wellness during this time of social distancing?

liberstina [14]

Answer: We can think differently about maintaining social wellness during this time of social distancing by (consider the following)

Explanation: If you are in a crowded space, try to keep 6 feet of space between yourself and others at all times, and wear a cloth face covering. Cloth face coverings are especially important in times when physical distancing is difficult.

Pay attention to any physical guides, such as tape markings on floors or signs on walls, directing attendees to remain at least 6 feet apart from each other in lines or at other times. Allow other people 6 feet of space when you pass by them in both indoor and outdoor settings.

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3 years ago

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Select all the species that are ions. HCl NaCl NH4+ H2PO4- CCl4 H3O+

nata0808 [166]

Answer:

NH₄⁺

H₂PO₄⁻

H₃O⁺

Explanation:

An ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.

Ion may be positively charged "cation" or negatively charged "anion".

Neutral molecule has a net charge of zero.

So, the species that are ions are:

NH₄⁺

H₂PO₄⁻

H₃O⁺

4 0

4 years ago

Identify the following elements based on the information provided:

leonid [27]

Answer:

answer

Explanation:

answer

5 0

3 years ago

When C-14 decays, it forms nitrogen, a(n) _____ particle, and a(n) _____.

aev [14]

c. alpha ; neutrino. Hope it helps

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4 years ago

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For an atmospheric pressure of 97.3 kPa (abs) determine the heights of the fluid columns in barometers containing one of the fol

kaheart [24]

Answer:

Follows are the solution to this question:

Explanation:

In the given question firstly we need to calculate the height of the pressure formula with in the vapor pressure, that includes the pressure, and its formula is:

$p(atm)_{vp} = \gamma .h +P_{vp}$

$\to \boxed{ h = \frac{p(atm)_{vp} - p_{vp}}{\gamma}}$

The vapour pressure where $_{vp}$ pays any attention. Next mercury measurement,Ethyl alcohol and water.

for mercury calculation:

$h_{Hg \ vp } =\frac{101 \times 10^3 \frac{N}{m^2}- 1.6 \times 10^{-1} \frac{N}{m^2}}{133 \times 10^3 \frac{N}{m^3}}$

$=\frac{101000- 0.16 }{133000}\\\\ =\frac{100999.84}{133000}\\\\= 0.759$

In the next step we calculate water value:

$h_{H_{2}0 \ vp } =\frac{101 \times 10^3 \frac{N}{m^2}- 1.77 \times 10^{3} \frac{N}{m^2}}{9.80 \times 10^3 \frac{N}{m^3}}$

$=\frac{101000- 1770}{9800}\\\\=\frac{99230}{9800}\\\\= 10.125$

In the last step, now we calculate the value of ethyl alchohol:

$h_{EA \ vp } =\frac{101 \times 10^3 \frac{N}{m^2}- 5.9 \times 10^{3} \frac{N}{m^2}}{7.74 \times 10^3 \frac{N}{m^3}}$

$=\frac{101000 - 5900 }{7740}\\\\ =\frac{95100 }{7740}\\\\=12.286$

The following would be the precise measurement of the heights without

Pressure of the vapour:

$a) h_{Hg} = \frac{101\times 10^3 \frac{N}{m^2}}{133\times 10^3 \frac{N}{m^3}} \\\\$

$= \frac{101 000 }{133000 } \\\\= \frac{101}{133 } \\\\= 0.759$

$\\\\b) h_{H_{2} o} = \frac{101\times 10^3 \frac{N}{m^2}}{9.80 \times 10^3 \frac{N}{m^3}}$

$= \frac{101}{9.80 }\\\\=10.30$

$\\\\c) h_{EA} = \frac{101\times 10^3 \frac{N}{m^2}}{7.74 \times 10^3 \frac{N}{m^3}}$

$= \frac{101}{7.74 } \\\\=13.04$

It may draw the substantial inference from of the calculated values. For the very first time. Mercury indicators and vapour pressure effects are insignificant and necessary height is within acceptable values for the mercury barometer tube (imagine). The alcohol barometer tube 12 metres high!).

7 0

3 years ago