WILL GIVE BRAINLIEST
1 answer:
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Check the picture 1.
The regions contained in an odd number of these 5 circles are
the pink colored region, contained only in the circle with radius 2,
and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.
So what we need to determine is the "area pink + area yellow".
Consider the second picture.
Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.
the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.
Thus, the overall yellow region is
The purple area is:
Area of large circle - 4*(Area of 1 small circle) + yellow region.
(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)
Finally, the total area is :
(units squared)
Answer:
square units
The regions contained in an odd number of these 5 circles are
the pink colored region, contained only in the circle with radius 2,
and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.
So what we need to determine is the "area pink + area yellow".
Consider the second picture.
Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.
the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.
Thus, the overall yellow region is
The purple area is:
Area of large circle - 4*(Area of 1 small circle) + yellow region.
(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)
Finally, the total area is :
Answer:
Answer:
See picture below
Step-by-step explanation:
To graph properly, remember that:
- The y intercept of the function, is the value of the function when x=0, and tells (in this case y=1 is the intercept). Locate this point in the graph.
- The x intercept, which is the value of x when y=0 is x=1. Locate it in the graph.
- You now have two points of a straight line: join this two points and you would have done it!
