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Dovator [93]
2 years ago
13

What is an equation of the line that passes through the points ( 4,8) and (1,-1)?

Mathematics
1 answer:
Nonamiya [84]2 years ago
3 0

Answer: y=3x-4

Step-by-step explanation: Use the slope formula and slope-intercept form y=mx+b to find the equation.

Hope this helps you out! ☺

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6. Write an equation of a line parallel to y = 3x + 9 and goes through the point (-1,5).
lisabon 2012 [21]

Answer: The equation parallel to the line is y=3x+8

Step-by-step explanation: Parallel lines have the same gradients, wr have a gradient for the above line which 3. The standard formula for the linear equation is y=mx+c

We have to calculate c since we have x and y.

y=mx+c

5= 3(-1)+c

c=8

The equation become y=3x+8

4 0
2 years ago
Modeling Compound Interest In Exercise, complete the table for an account in which interest is compounded continuously.
Mademuasel [1]

Answer:

This problem requires us to calculate, the value of investment after 10 and 25 years, and also tell the time after which intial investment amount will double. Investment rate and initial investment amount is given in the question.

Value of investment after 10 year = 600(1+8%)^10 = $ 1,295

Value of investment after 25 year = 600(1+8%)^25 = $ 4,109

Time after which investment amount double (n)

1200 = 600 (1.08)^n

Log 2 = n log 1.08

n = 9 years

6 0
3 years ago
A parallelogram has one angle that measures 80 degrees. What are the measures of the three other angles in the parallelogram?
san4es73 [151]
The opposite angle is also 80°. since consecutive angles must total 180, the other 2 angles are 100 each. 100+100+80+80=360, as needed for a parallelogram
6 0
3 years ago
Read 2 more answers
the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
miss Akunina [59]
The equation of a circle in standard form is

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center of the circle, and r is the radius if the circle.

We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.

M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).

To find the radius, we find the length of the given diameter and divided by 2.

d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}

d = \sqrt{144 + 64}

d = \sqrt{208}

r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}

(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2

x^2 + (y - 2)^2 = 52
7 0
3 years ago
Write the integers in order from least to greatest
Charra [1.4K]
#7) -7,-2,0,3,4
#8) -9,-6,-5,1,8
8 0
3 years ago
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