Answer:
t = 36
Step-by-step explanation:
If one of the roots is "a", the equation can be factored as ...
(5x -a)(x -a) = 0
5x^2 -6ax +a^2 = 0
Comparing terms to the given equation, we see that ...
-6ax = -36x
a = 6 . . . . . . . . divide by -6
Then ...
a^2 = t
36 = t . . . . . . . substitute 6 for a
_____
The roots are 6 and 6/5.
fifty-seven is how you spell 57 in word form.
Solve for x over the real numbers:
x^3 (x^2 - 4) = 0
Split into two equations:
x^3 = 0 or x^2 - 4 = 0
Take cube roots of both sides:
x = 0 or x^2 - 4 = 0
Add 4 to both sides:
x = 0 or x^2 = 4
Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2
X= -2
look at the 6x-12 you divide -12 by 6 and get x=-2
