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3 years ago

To prepare for a laboratory?

Chemistry

1 answer:

yKpoI14uk [10]3 years ago

6 0

Answer:

You have to prepare for the lab (Materials, work, paper etc.)

Set up the lab know where the lab will be taking place

Read thru the experiment before doing the lab

Make a hypothesis

Write down notes, observations, measures anything important to help with the lab!

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Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0

olya-2409 [2.1K]

Answer:

$pH=-1.37$

Explanation:

We are given that 25 mL of 0.10 M $CH_3COOH$ is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of $CH_3COOH=25mL=0.025 L$

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL= $\frac{35}{1000}=0.035 L$

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of $CH_3COOH$ =0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+= $0.10\times 0.025$ =0.0025 moles

Number of moles of $OH^-=0.10\times 0.01$ =0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+= $\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L$

pH=-log [H+]=-log [4.28 $\times 10^{-2}$ ]=-log4.28+2 log 10=-0.631+2

$pH=-1.37$

6 0

3 years ago

If 25 mol of C8H18 are available, how many mol of CO2 can be produced

Nady [450]

Answer:

200 mol

Explanation:

2C8H18+25O2=16CO2+18H2O

2 mol → 16 mol

25 mol → X mol

X=25×16÷2=200

7 0

3 years ago

For motion maps that illustrate accelerated motion what does a new level indicate

zhenek [66]

Oh that’s crazy I need help

3 0

3 years ago

What did early Greeks believe the world was made of

timurjin [86]

Answer: made up of an infinite number of indestructible atoms in unpredictable motion.

3 0

3 years ago

What is the molarity of a solution of sulfuric acid if 49.0 mL of it are neutralized by a titration

vaieri [72.5K]

Answer:

THE MOLARITY OF THE ACID IS 0.232M

Explanation:

Molarity is the number of moles of solute per liter of a solution.

In titration, the molarity of the acid and the molarity of the base are related by this equation:

Ca VA / CbVb = na / nb

Ca = concentration of the acid = ?

Va = volume of the acid = 49 mL

Cb = concentration of the base = 0.333M

Vb = volume of the base = 68.4mL

Na = number of mole of acid = 1

Nb = number of mole of base = 2

Equation for the reaction:

H2SO4 + 2NaOH --------> Na2SO4 + 2H2O

Solving for the molarity of the acid, we have :

Ca = CbVbNa / VaNb

Ca = 0.333M * 68.4mL * 1 / 49mL *2

Ca = 22.7772 * 10^-3 / 98 *10^-3

Ca = 0.232M

The molarity of the acid is therefore 0.232M.

8 0

3 years ago

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