There would be 0.8315 moles
We have a balanced equation:
2 Al+ 3 CuSO4 ⇒ Al2(SO4)3+ 3 Cu
1.85 g Al* (1 mol Al/ 26.98 g Al)* (3 mol Cu/ 2 mol Al)* ( 63.55 g Cu/ 1 mol Cu)= 6.54 g Cu.
(Note that the units cancel out so you get the answer)
6.54 g Cu* (56.6/100)= 3.70 g Cu.
The final answer is 3.70 g Cu~
Given that there is 4.0 g of He, 6.5 g of Ar, and 10.0 g of Ne :
So, first all these masses are converted into moles:




Total Number of moles = 1 + 0.1627 + 0.4955 = 1.658 mol

= 
Answer:
The order of the reaction is 1.
Explanation:

The rate law of the reaction ;
![R=k[N_2O_5]^x](https://tex.z-dn.net/?f=R%3Dk%5BN_2O_5%5D%5Ex)
The rate of the reaction from T = 0 s to 25 s,
to
respectively.

..[1]
The rate of the reaction from T = 25 s to 50 s,
to
respectively.

..[2]
[1] ÷ [2]
![\frac{0.00712 M/s}{0.0058 M/s}=\frac{k[0.822 M]^x}{k[0.677 M]^x}](https://tex.z-dn.net/?f=%5Cfrac%7B0.00712%20M%2Fs%7D%7B0.0058%20M%2Fs%7D%3D%5Cfrac%7Bk%5B0.822%20M%5D%5Ex%7D%7Bk%5B0.677%20M%5D%5Ex%7D)
Solving for x:
x = 1.05 ≈ 1
The rate law of the reaction ;
![R=k[N_2O_5]^1](https://tex.z-dn.net/?f=R%3Dk%5BN_2O_5%5D%5E1)
The order of the reaction is 1.