Answer:
58.94 mL
Explanation:
V1 = 48.3 mL V2 = v mL
T1 = 22 degree celsius OR 295 k T2 = 87 degree celsius OR 360 k
We will use the gas equation:
PV = nRT
Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,
we can say that
V / T = k , (where k is a constant)
Since this is the first case,
V1 / T1 = k --------------------(1)
For case 2:
Since we have the same constants, the equation will be the same
V / T = k (where k is the same constant from before)
V2 / T2 = k (Since this is the second case) ------------------(2)
From (1) and (2):
V1 / T1 = V2 / T2
Now, replacing the variables with the given values
48.3 / 295 = v / 360
v = 48.3*360 / 295
v = 58.94 mL
Therefore, the final volume of the gas is 58.94 mL
Answer:
In Diels alder reaction
It's an Adduct that is fromed from the reactants
Explanation:
I.e diene + dienophile= Adduct
E.g 1,3-butadiene + ethene = cyclohexene
Answer:
Explanation:
The question is asking, "At what temperature does the vapour pressure of water equal 3.4 atm?"
To answer this question, we can use the Clausius-Clapeyron equation:
Data:
p₁ = 1 atm; T₁ = 373.15C
p₂ = 3.4atm; T₂ = ?
R = 8.314 J·K⁻¹mol⁻¹
(The enthalpy of vaporization changes with temperature. Your value may differ from the one I chose.)
Calculation:
