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user100 [1]
3 years ago
12

I need to use the power rule (if m and n are real numbers and x doesn't equal 0, then (x^m)^n = x^mn... ) to simplify this fract

ion: (2x^2 y^-2 / y^5)^-3
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Answer:

= 2x^{-6}y ^{21}\\\\

Step-by-step explanation:

Given the indicinal expression  (2x^2 y^-2 / y^5)^-3

In indices

(x^m)^n = x^{mn

Applying to solve the question

(2x^2 y^{-2} / y^5)^{-3}\\\\= \frac{2x^{-6}y^6}{y^{-15}}\\=  2x^{-6} * \frac{y^6}{y^{-15}} \\= 2x^{-6} * y ^{6-(-15)}\\= 2x^{-6} * y ^{6+15}\\= 2x^{-6} * y ^{21}\\= 2x^{-6}y ^{21}\\\\

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Gerardo made the following scores on his first semester science tests: 80, 85, 85, 87, 97, 100. Which measure would he use in su
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4 0
3 years ago
The price of some houses in a neighborhood are shown below: House Price A $120,000 B $130,000 C $140,000 D $150,000 E $1,110,000
LenaWriter [7]

Answer:

To infer a price for the houses in that neighborhood, it is better to use the median.

Step-by-step explanation:

We have the following prices:

$ 120,000

$ 130,000

$ 140,000

$ 150,000

$ 1,110,000

Now, if we do it for the median, it is the best option, because there is a very distant value and the median is not much affected. The value that is inferred through the average is $ 140,000, a value close to the first 4 houses.

If we do it by the mean, the value would be:

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a value very far from all the prices of the houses, this is due to the value so far from the last house.

In other words, to infer a price for the houses in that neighborhood, it is better to use the median.

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4 years ago
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Step-by-step explanation:

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w = 35
8 0
3 years ago
Read 2 more answers
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