Answer:
- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.
- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.
- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.
Explanation:
Hello,
It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:
In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:
![pH=-log([H^+])\\](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%5C%5C)
![[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
![pOH=-log([OH^-])](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29)
![[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.
Best regards.
Answer:
11 1/2 cm I think lol
Explanation:
it is in between the 11 and 12 mark
Answer:
4.77mol is the correct answer
Answer:
it means compound A is <u>less</u> polar than compound B
Explanation:
It is sure that the more polar the solvent, the faster compounds elute, regardless of the compounds polarity. This means changing the solvent polarity cannot change the order compounds elute from a TLC or column. This may seem non intuitive, as it would seem that a polar solvent would move a polar compound farther than a nonpolar compound.
Answer:
F⁻(aq) + H⁺(aq) ⇄ HF(aq)
Explanation:
When aqueous solutions of potassium fluoride and hydrochloric acid are mixed, an aqueous solution of potassium chloride and hydrofluoric acid results. The corresponding molecular equation is:
KF(aq) + HCl(aq) ⇄ KCl(aq) + HF(aq)
The full ionic equation includes all the ions and the molecular species. HF is a weak acid so it exists mainly in the molecular form.
K⁺(aq) + F⁻(aq) + H⁺(aq) + Cl⁻(aq) ⇄ K⁺(aq) + Cl⁻(aq) + HF(aq)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.
F⁻(aq) + H⁺(aq) ⇄ HF(aq)
