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Sidana [21]
3 years ago
9

Scoring Scheme: 3-3-2-1 When you use the half reaction method to balance the redox reaction between one mole of NBS and ascorbic

acid to give L-dehydroascorbic acid and succinimide, how many moles of electrons are transferred?

Chemistry
1 answer:
erica [24]3 years ago
6 0
<span>In the redox reaction between one mole of NBS and ascorbic acid, ascorbic acid undergoes oxidation reaction to form </span><span>L-dehydroascorbic acid.

On other hand, N-bromo</span>succinimide (NBS) undergoes reduction to form <span>succinimide.

Electron transferred during this process is two. Complete reaction is attached below for quick reference.

Thus, one molecule of NBS reacts with one molecule of </span>ascorbic acid, during this redox reaction. For each molecule reacting, two electrons are transferred. 

Thus, when one mole of NBS reacts with one mole of ascorbic acid, 2 x Na moles of electrons will be transferred. It may be noted here that, Na = Avagadro's number = 6.022 X 10^23.

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Which of the following is the correct chemical formula for Ca and F? CaF Ca2F CaF2
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4 0
3 years ago
Fluorine-21 has a half life of approximately 5 seconds. You have 340 grams, what fraction of the original nuclei would remain af
madreJ [45]
The half life equation is -->P(t) = Pi (0.5) ^ (t/c)
c is equal to the element to reach its half-life (5 seconds)t is equal to the duration of time the element is expose to (20 seconds)Pi is the initial amount (340)0.5 is the base of this exponential function to represent half-life.P(t) is the expression for the function of time

P(20) = 340 (0.5)^20/5P(20) = 340 (0.5) ^4P(20)= 21.25 grams
Fraction = P(t)/Pi              = P(20)/Pi              =21.25/340              =1/16
Therefore, when given 20 seconds, 340 grams of Fluorine-21 will degrade to 21.25 grams OR 1/16 of its original mass.
Hope this method helps! (This is my answer btw, I think you may have accidentally posted twice?)
7 0
3 years ago
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