A double displacement reaction is one in which the positive and negative ion in one reactant switch places with the positive and negative ions of the second reactant forming two new products.
In general if we have two reactants AB and CD, the double displacement reaction can form the following products:
A⁺B⁻ + C⁺D⁻ → C⁺B⁻ + A⁺D⁻
In the given example:
K₂SO₄ + Pb(NO₃)₂ → PbSO₄ + 2KNO₃
Ans: B)
One of the products would be PbSO₄
Answer: 177g
Explanation:
Aw 12 = 6.02214076*10^23 atoms
mass = 12*88.70^23/6.022*10^23
Answer:
Well you should wear boots.
Explanation:
Boots because most winterized boots have tread on the bottom, allowing you to grip the ice better. They will help prevent you from slipping , and are even good for walking up slippery hills.
Explanation:
1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.
(At constant temperature and number of moles)
- When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
- When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.
2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.
(At constant pressure and number of moles)
- The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
- When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.
3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.
(At constant temperature and pressure)
When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.
Answer:
Percent by mass of water is 56%
Explanation:
First of all calculate the mass of hydrated compound as,
Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g
Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g
Mass of Oxygen = O × 14 = 16 × 14 = 224 g
Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g
Mass of Na₂S0₄.10H₂O = 322.24 g
Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...
Mass of water = 10 × 18.02
Mass of water = 180.2 g
Now, we will apply following formula to find percent of water in hydrated compound,
%H₂O = Mass of H₂O / Mass of Hydrated Compound × 100
Putting values,
%H₂O = 180.2 g / 322.24 g × 100
%H₂O = 55.92 % ≈ 56%
