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2 years ago

Here is 25 points check out my other ones to get 100 points just show me love and i will be ok :]

Mathematics

2 answers:

Neporo4naja [7]2 years ago

7 0

Answer:

I'm a bit late in seeing this... Good thing I followed you! Thanks again!

m_a_m_a [10]2 years ago

6 0

it's a good thing people didn't answer these.

this is like the 3rd I've answered

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Which expression is equivalent to 3^8 times 3^7?

m_a_m_a [10]

Answer:

1/3⁵⁶ is the answer i think if it's not then i am sorry

5 0

2 years ago

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let X = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, λ = 11/ hour.

The random variable X follows a Poisson distribution with parameter λ = 11.

The probability mass function of X is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in t hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of t as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

3 years ago

A farmer wants to build a new grain silo. The shape of the silo is to be a cylinder with a hemisphere on the top, where the radi

notsponge [240]

Answer:

The radius of the silo should be $16\ ft$

Step-by-step explanation:

we know that

The volume of the grain silo is equal to the volume of the cylinder plus the volume of a hemisphere

$V=\pi r^{2} h+\frac{4}{6}\pi r^{3}$

we have

$V=35,500\pi\ ft^{3}$

$h=4D=8r$

substitute the values and solve for r

$35,500\pi=\pi r^{2} (8r)+\frac{4}{6}\pi r^{3}$

Simplify

$35,500=r^{2} (8r)+\frac{4}{6}r^{3}$

$35,500=8r^{3}+\frac{2}{3}r^{3}$

$35,500=\frac{26}{3}r^{3}$

$r^{3}=35,500*(3)/26$

$r=16\ ft$

5 0

3 years ago

Consider the function f(x)=(x-9)/(x^3-81x) Find the vertical asymptote(s) of f(x)

enyata [817]

Well, here's a harder one
Basically, to find a vertical asymptote, we set the denominator to 0. Like this:
x^3 - 81x = 0
Then we solve for x.
x(x^2 - 81) = 0
x(x+9)(x-9) = 0
x = 0, 9, -9
There are vertical asymptotes at x = 0, x = 9, and x = -9.

4 0

3 years ago

Read 2 more answers

Write an equation of the line that passes through the given points. (-2,5) and (1,2)

Anon25 [30]

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-2)}}}\implies \cfrac{-3}{1+2}\implies \cfrac{-3}{3}\implies -1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}[x-\stackrel{x_1}{(-2)}] \\\\\\ y-5=-(x+2)\implies y-5=-x-2\implies y=-x+3$

7 0

2 years ago