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3 years ago

3/4 times (-1/3) ?????

Mathematics

2 answers:

DIA [1.3K]3 years ago

4 0

Answer:

Step by step explanation:

$\frac{3}{4} \times ( \frac{ - 1}{3} )$

Multiplying a positive and negative equals a negative:

$( + ) \times ( - ) = ( - )$

$- \frac{3}{4} \times \frac{1}{3}$

Reduce the number with the greatest common factor 3

$- \frac{1}{4}$

Hope this helps...

Good luck on your assignment...

Snowcat [4.5K]3 years ago

3 0

Answer:

-1/4

Step-by-step explanation:

You multiply the numerators, 3 multiplied by -1=-3.

Then the denominators, 4 multiplied by 3=12.

This means the answer is -3/12, but then you can simplify it to -1/4.

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4 years ago

WILL MEDAL help me if please

nordsb [41]

1. Use the FOIL method (x+9)(x+9)
First, outer, inner, last
$x^{2} +9x+9x+81$
Add your like terms
$x^{2} +18x+81$

2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.

3. $-5x(5 x^{3} +10 x^{2} -6x+3)$

4. Since it is the perimeter, we add the 3 together.
$(2 x^{2} +4x-3)+(-3 x^{2} -3)+(5x+19)$
Add the like terms together:
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8 0

3 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

likoan [24]

Answer:

A) 3%

B) Product A

Step-by-step explanation:

Exponential Function

General form of an exponential function: $y=ab^x$

where:

a is the initial value (y-intercept)
b is the base (growth/decay factor) in decimal form
x is the independent variable
y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

Part A

Product A

Assuming the function for Product A is exponential:

$f(x) = 0.69(1.03)^x$

The base (b) is 1.03. As b > 1 then it is an increasing function.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, product A is increasing by 3% each year.

Part B

$\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100$

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

$\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%$

Check using different two consecutive values of f(t):

$\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%$

Therefore, as 3% > 1%, Product A recorded a greater percentage change in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

a = 10,100
b = 1.01
n = t - 1 (as the initial value is for t = 1 not t = 0)

$\implies f(t) = 10100(1.01)^{t-1}$

To check this, substitute the values of t for 1 through 4 into the found function:

$\implies f(1) = 10100(1.01)^{1-1}=10100$

$\implies f(2) = 10100(1.01)^{2-1}=10201$

$\implies f(3) = 10100(1.01)^{3-1}=10303.01$

$\implies f(4) = 10100(1.01)^{4-1}=10406.04$

As these values match the values in the given table, this confirms that the found function for Product B is correct and that Product B increases by 1% per year.

4 0

2 years ago