I need this help due tomoorw

Mathematics

1 answer:

Lisa [10]3 years ago

6 0

Answer: It's the last one. If you ever need help with a question like that, just use the desmos graphing calculator. You just put the equation in and it shows you the graph would look for that equation.

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What is the slope of the line that contains the points (-2,5) and (6, -3)?

mel-nik [20]

Answer:

-1

Step-by-step explanation:

Attached is a picture of slope formula:

1) Apply slope formula given two points:

(5--3)/(-2-6)

2) Simplify:

8/-8

3) Divide:

-1

3 0

3 years ago

Read 2 more answers

Write the ratio as a ratio of a whole numbers using fractional notation 6 1/2 to 15 1/6

motikmotik

$\bf 6\frac{1}{2}:15\frac{1}{6}\qquad 
\begin{cases}
6\frac{1}{2}\implies \cfrac{6\cdot 2+1}{2}\\\\
15\frac{1}{6}\implies \cfrac{15\cdot 6+1}{6}
\end{cases}\implies \cfrac{ \frac{6\cdot 2+1}{2}}{\frac{15\cdot 6+1}{6}}\\\\
-----------------------------\\\\
\cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\qquad thus
\\\\\\
\cfrac{6\cdot 2+1}{2}\cdot \cfrac{6}{15\cdot 6+1}$

simplify away

5 0

4 years ago

Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$