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enot [183]
3 years ago
11

a certain computer loses half of its value every two years. after how many years will the computer be worth 12.5% of the initial

value?
Mathematics
2 answers:
Juliette [100K]3 years ago
7 0

After every 2 years, a certain computer loses half of its value. Let the initial price of the computer be x .

So after 2 years, the price reduce to half of its price , that is 0.5x .

After 4 , years, the price reduce to half of its price , that is 0.25x .

After another 2 years, that is after 6 years, the price reduce to half, that is 0.125 x .

Therefore after 6 years, the price of the computer worth 12.5% of the initial value .

lukranit [14]3 years ago
7 0
................. .................
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A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i
lutik1710 [3]

Answer: 1-(\frac{364}{365})^n

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^x, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

p=\dfrac{1}{365}

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

P(x\geq1)=1-P(x

Hence, the probability there is at least one day in a year when nobody has a birthday =1-(\frac{364}{365})^n

5 0
3 years ago
X and y are positive integers. explain why incorrect to claim that
dedylja [7]

You can find counterexamples to disprove this claim. We have positive integers that are perfect square numbers; when we take the square root of those numbers, we get an integer.

For example, the square root of 1 is 1, which is an integer. So if y = 1, then the denominator becomes an integer and thus we get a quotient of two integers (since x is also defined to be an integer), the definition of a rational number.

Example: x = 2, y = 1 ends up with \frac{2}{\sqrt{1}} = \frac{2}{1} which is rational. This goes against the claim that x/\sqrt{y} is always irrational for positive integers x and y.

Any integer y that is a perfect square will work to disprove this claim, e.g. y = 1, y = 4, y= 9, y = 16. So it is not always irrational.

4 0
3 years ago
Compare 9.36 and 9.359
Sati [7]

Try this option (this is not the only way!):

1. the rule: if 'number_1' - 'number_2' > 0, then number_1>number_2. If 'number_1'-'number_2'<0, then number_2>number_1.

2. according to the rule above: 9.36-9.359=0.001. 0.001>0, it means, 9.36>9.359.

6 0
4 years ago
Solve for the indicated variable in the parentheses<br><br> P = IRT Solve for (T)
KATRIN_1 [288]
P = IRT 

T=P/(IR)

hope helped 
8 0
3 years ago
U = 6i – 10j<br> g= -81 – 11j<br> Find: -3u + 5g
VARVARA [1.3K]

Answer:

-3u + 5g =-58i -25j

Step-by-step explanation:

Given

u = 6i - 10j

g=-8i - 11j

Required

-3u + 5g

We have:

-3u + 5g

This gives:

-3u + 5g = -3(6i - 10j) + 5(-8i - 11j)

Open bracket

-3u + 5g = -18i + 30j - 40i - 55j

Collect like terms

-3u + 5g = -18i - 40i+ 30j  - 55j

-3u + 5g =-58i -25j

6 0
3 years ago
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