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vagabundo [1.1K]
2 years ago
9

19 students in the cross is your favorite sport. Explain how to use a circle graph to find the total number of students surveyed

. 20% chose swimming. 42% chose volleyball and 38% chose lacrosse
Mathematics
1 answer:
kompoz [17]2 years ago
6 0
Tbh I don’t know the answer
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PLEASE ANSWER THIS QUESTION !! 20 POINTS AND BRAINLIEST !!
lutik1710 [3]

Answer:

B

Step-by-step explanation:

If they have no solutions, the lines must not intersect.

If they don't intersect, they must be parallel

8 0
2 years ago
Read 2 more answers
Can any one pls help me with 14,15 pls tysm! have a great day :D
Temka [501]

Answer:

14.$403.46 or  $403.50(rounded)

15.11.55 or 11.60(rounded)

Step-by-step explanation:

Commission is when you get a percent added to the amount of money you have already so with that being said-397.50+1.5%

She uses 24% so with that being said to find the amount left you have to subtract the percent from the original amount-15.2-24%

6 0
2 years ago
Find the value of x.
Jet001 [13]

Answer:

Value of x=-12

Step-by-step explanation:

The given triangle is isosceles

Here

m\angle2+m\angle2+36^0=180^0\\\\2m\angle2=144^0\\\\m\angle2=72^0\\\\x+84=72\\\\x=72-84\\\\=-12

3 0
2 years ago
A triangle is graphed on a coordinate plane, with a vertex located at a point represented by (x,y).
Papessa [141]

Answer:

The image of the triangle is smaller than the triangle.

Step-by-step explanation:

5 0
2 years ago
DETERMINA EL VOLUMEN DE UN PRISMA PENTAGONAL QUE TIENE LAS SIGUIENTES MEDIDAS: LADO 6.1 CM, APOTEMA 4.5, ALTURA 12.5CM DEL PRISM
Anna71 [15]

Answer:

837.23 cm³

Step-by-step explanation:

La fórmula para el volumen de un prisma pentagonal se da como:

1/2 (5 s × a) × h

Dónde:

s = longitud lateral

a = Apotema

h = altura

De la pregunta anterior:

s = largo de lado = 6.1 cm

a = Apotema = 4.5 cm

h = Altura = 12.5 cm

Por lo tanto:

El volumen del prisma pentagonal =

1/2 (5 × 6.1 × 4.5) × 12.5

= 1/2 × 137.25 × 12.5

= 837.225 cm³

Aproximadamente = 837.23 cm³

4 0
2 years ago
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