Show that KEYS is a square if K (-2, 4) ,E (4,2 ), Y(2,-4 ) ,S (-4, -2) are the co- ordinates of the vertices.

Mathematics

1 answer:

Lyrx [107]3 years ago

4 0

Answer:

KEYS is a square

Showing as plotted and connected points

See the attached

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Rounded to the nearest whole number, how many 2ft by 2ft squares will fit into circle that has a diameter of 20 feet?

seraphim [82]

Answer:

Step-by-step explanation:

The area of a circle is pi*radius^2; the radius of this circle is 10 (20/2=10). Our area is then 100pi or ~314 square feet. A 2x2 square takes up 4 feet. 314/4 is equal to 78.5, or when rounded, 79

3 0

4 years ago

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$