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3 years ago

Describe how Fossil fuels supply chemical potential energy and transform it into thermal energy

Chemistry

1 answer:

Kruka [31]3 years ago

6 0

Explanation:

fossil fuels produce oil which is a chemical energy source. oil can be a by product of petrol which means when burnt can produce heat

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calculate the molarity of MgCl2 in the following solution: 5.34 g of MgCl2 is dissolved and diluted to 214 mL of solution.

anyanavicka [17]

$\quad\hookrightarrow\quad \sf {0.262M }$

<h3>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

We are given that :

Weight of $\sf MgCl_{2}$ = 5.34g
Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( $\sf MgCl_{2}$ ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

$\quad\longrightarrow\quad \sf {M = \dfrac{n}{V} }$ ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

Where,

M = molarity
n = number of moles
V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

$\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}$ ‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

Where,

n = number of moles
m = molar mass
w = actual mass

Therefore,

$\implies\quad \tt {n =\dfrac{w}{m} }$

$\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}$

$\implies\quad{\pmb{ \tt {n = 0.056 mol}} }$

Putting the values in equation ( 1 ):

$\implies\quad \tt {M=\dfrac{n}{V} }$

$\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}$

$\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}$

7 0

2 years ago

How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?

Katen [24]

2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g

5 0

3 years ago

A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO

Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems is:

$\frac{N}{N_0}=(\frac{1}{2})^n$

where, $N_0$ is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

$4.536days(\frac{24hours}{1day})$

= 108.864 hours

So, $n=\frac{48.0}{108.864}$ = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

$\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1$