Two fractions are equivalent if the product of the numerator of the first and the denominator of the second is equal to the product of the numerator of the second and the denominator of the first.
4 x 2 ___ 16 x 0.25
8 is not equal to 4
Thus, they are not equivalent.
Answer:
Step-by-step explanation:
Given:
Type of Flowers = 5
To choose = 4
Required
Number of ways 4 can be chosen
The first flower can be chosen in 5 ways
The second flower can be chosen in 4 ways
The third flower can be chosen in 3 ways
The fourth flower can be chosen in 2 ways
Total Number of Selection = 5 * 4 * 3 * 2
Total Number of Selection = 120 ways;
Alternatively, this can be solved using concept of Permutation;
Given that 4 flowers to be chosen from 5,
then n = 5 and r = 4
Such that
![nPr = \frac{n!}{(n - r)!}](https://tex.z-dn.net/?f=nPr%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n%20-%20r%29%21%7D)
Substitute 5 for n and 4 for r
![5P4 = \frac{5!}{(5 - 4)!}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%21%7D%7B%285%20-%204%29%21%7D)
![5P4 = \frac{5!}{1!}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%21%7D%7B1%21%7D)
![5P4 = \frac{5*4*3*2*1}{1}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%2A4%2A3%2A2%2A1%7D%7B1%7D)
![5P4 = \frac{120}{1}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B120%7D%7B1%7D)
![5P4 = 120](https://tex.z-dn.net/?f=5P4%20%3D%20120)
Hence, the number of ways the florist can chose 4 flowers from 5 is 120 ways
It would be 0.008 because you line up the decimals and multiply
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
I don’t see an attachment