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wlad13 [49]
3 years ago
5

PLEASE HELP ASAP! PLEASE BE HONEST! ALGEBRA

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

The answer is (2,-2)

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What is the area of a 320 ft semicircle?
Sever21 [200]

Answer: they do not have enough info but I will try my best to answer  if im wrong its not my fault  so please add more info

Solution

2. I know that for a Semi-Circle Area = 320 . From this find out Area of the Semi-Circle.

Solution:

Here Area=320(Given)

Area=

πr2

2

r2=

Area⋅2

π

r2=

320⋅2

22

7

r=14.2701

Diameter(d)=2r

=2⋅14.2701

=28.5402

Circumference=πr

=

22

7

⋅14.2701

=44.849

Perimeter=πr+2r

=

22

7

⋅14.2701+2⋅14.2701

=44.849+28.5402

=89.6979

Step-by-step explanation:

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2 years ago
For the function f(x)= V2x + 6, find all values x for which f(x) = 18.
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3 years ago
Write an expression to represent: Three more than the product of two and a number x.
andriy [413]

Answer:

2x + 3

Step-by-step explanation:

product means to multiply, hence

the product of 2 and a number x = 2 × x = 2x

3 more than means add on 3, thus

expression is 2x + 3


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3 years ago
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Please help i need help please
posledela

Answer:

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Step-by-step explanation:

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3 years ago
A medication has a half-life of 4 hours after it enters the bloodstream. A nurse administers a dose of 225 milligrams to a patie
Mandarinka [93]

Answer:

The half life of a material is the time that a given quantity A of the material, decays into its half.

We know that the half-life is 4 hours, then we have the equation:

Q(t) = A*r^t

Where A is the initial quantity, and t is the number of hours.

and we have that r^4 = 1/2 (so when t = 4, we will have half of A)

then r = (1/2)^(1/4) = 0.84

Then our relation is

Q(t) = A*0.84^t

We have that A = 225mg,

at 1:00 pm. we have one hour after noon, so here we need to use t = 1.

Q(1) = 225mg*0.84^1 = 189.2mg

At 7:00 pm, we have 7 hours since noon, so here we need to use t = 7

Q(7) = 225mg*0.84^7 = 66.4mg

8 0
4 years ago
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