Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation
√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8
Answer:
I think it would be 2(8) + 3(5) = x or = 31
Step-by-step explanation:
Answer:thats
Step-by-step explanation:
its
Answer:
Step-by-step explanation:
The answer to this should be 2(3x+5)
The simplified answer of this is 6x+10
I hope I helped you out.
Answer:
S.A. = 138.16
Step-by-step explanation:
S.A. = πrl+πr²
3.14 x 4 = 12.56
12.56 x 7 =87.92
3.14 x 4 = 12.56
12.56 x 4 = 50.24
87.92 + 50.24 = 138.16
Let me know if this helps!