Can anyone help me with this formula?

Chemistry

1 answer:

pychu [463]3 years ago

4 0

Answer:

[1] P4 + [3] O2=[2] P2O3

Explanation:

you can first solve for amount of O2 in the equation because reactant had O2 and product had O3, so the amount of O2 should be 3 and amount of O3 should be 2, which gets u to 6 moles of oxygen for both reactant and product. then you can balance the P4, and 1 mols of P4 = 2 moles of P2, which matches with the amount of mols for O3 as well. therefore you can get P4 + 3O2 = 2P2O3

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Gaseous ethane (CH,CH,) will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO) and gaseous water (H2O). Supp

notka56 [123]

Answer:

0.00 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ 30.07 32.00

2CH₃CH₃ + 7O₂ ⟶ 4CO₂ + 6H₂O

Mass/g: 1.50 11.

2. Calculate the moles of each reactant

$\text{moles of C$_{2}$H}_{6} = \text{1.50 g C$_{2}$H}_{6} \times \dfrac{\text{1 mol C$_{2}$H}_{6}}{\text{30.07 g C$_{2}$H}_{6}} = \text{0.04988 mol C$_{2}$H}_{6}\\\\\text{moles of O}_{2} = \text{11. g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.34 mol O}_{2}$