Find the solution to the equation 1over 2 (t-6)=1
1 answer:
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Answer:
a
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
To calculate m use the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = B(- 4, 2) and (x₂, y₂ ) = C(- 2, - 2)
m = =
= - 2
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 2, - 2), then
- 2 = 4 + c ⇒ c = - 2 - 4 = - 6
y = - 2x - 6 ← equation of line through B and C
Answer:
see attached
Step-by-step explanation:
The equation is in the form ...
4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance
Comparing this to your equation, we see ...
p = 4, (h, k) = (3, 4)
p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...
vertex: (3, 4)
axis of symmetry: x = 3
focus: (3, 8) . . . . . 4 units up from vertex
directrix: y = 0 . . . horizontal line 4 units down from vertex
