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Cerrena [4.2K]
3 years ago
11

Find the solution to the equation 1over 2 (t-6)=1

Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

1/2(t-6)=1

1/2(t-6)=1x2

1/2(t-6)=2

t/2-6/2=2/1

t/2-3/1=2/1

t/2-3=2

t/2=2-3

t/2=-1

t/2=-1/1

t=-2x1

t=-2

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Hello can someone help me with this?
zalisa [80]

Answer:

  1. 1
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  7. -1
  8. -1/2
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3 years ago
Is 15 cm greater than or less than 150 mm
Alekssandra [29.7K]

Answer:

Those are the same measurment!

Step-by-step explanation:

Conversion:

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2 years ago
What other angles can be marked as congruent?
umka2103 [35]

Answer:

Option B

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Can someone answer this for me
ladessa [460]

The linear equation in standard form is:

6x - 7y = -11

Which is the last option.

<h3>How to get the equation of the line?</h3>

The line in slope-intercept form is written as:

y = a*x + b

We can see that the line passes through the points (-3, -1) and (1/2, 2), then the slope is:

a = \frac{2 - (-1)}{1/2 - (-3)}  = \frac{3}{3.5}  = \frac{6}{7}

Then we can write:

y = (6/7)*x + b

To find the value of b, we use the first point. It means that when x = -3, the value of y is -1, then we get:

-1 = (6/7)*-3 + b

-1 + 18/7 = b

-7/7 + 18/7 = b

11/7 = b

Then the equation is:

y = (6/7)*x + 11/7

If we multiply both sides by 7 we get:

7y = 6x + 11

Now we move the term with "x" to the left:

7y - 6x = 11

That is the line in standard form.

If we multiply both sides by -1, we get the last option:

6x - 7y = -11

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

8 0
2 years ago
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Please help! Brainliest
Mama L [17]

1.301

Explanation:

Given:

\log_a5 \approx 0.699 and \log_a2 \approx 0.301

Note that from the properties of logarithms,

\log_a20 = \log_a(5×4)

\:\:\:\:\:\:\:\:\:\:= \log_a(5×2^2)

\:\:\:\:\:\:\:\:\:\:=\log_a5 + \log_a(2)^2

\:\:\:\:\:\:\:\:\:\:=\log_a5 + 2\log_a2

\:\:\:\:\:\:\:\:\:\:\approx 0.699 + 2(0.301)

\:\:\:\:\:\:\:\:\:\:= 1.301

6 0
3 years ago
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