All categories

4 years ago

Find the solution to the equation 1over 2 (t-6)=1

Mathematics

1 answer:

Fynjy0 [20]4 years ago

6 0

Answer:

1/2(t-6)=1

1/2(t-6)=1x2

1/2(t-6)=2

t/2-6/2=2/1

t/2-3/1=2/1

t/2-3=2

t/2=2-3

t/2=-1

t/2=-1/1

t=-2x1

t=-2

You might be interested in

Factor this expression completely

Zigmanuir [339]

Answer:

Answer is A

Step-by-step explanation:

100× x is 100x

100 × 10 is 1000

6 0

4 years ago

Read 2 more answers

X+4

mr Goodwill [35]

Answer:

Step-by-step explanation:

(x + 4)/(x+4)(x-3)

= 1/(x-3)

solution is option 4

3 0

2 years ago

Jamie needs to determine the distance across a river. She selects a rock, R, on the opposite river bank. She finds a tree, T, on

valentina_108 [34]

RT = BT = 75

This is because she used the same angle from point C to mark point B, thus creating a symmetric right triangle.

Triangle BCT = Triangle RCT

8 0

4 years ago

Solve 2x - y = -6 if the domain is (-2,-1, 0, 1).

MAVERICK [17]

Answer:

y = 2, y = 4, y = 6, y = 8

Step-by-step explanation:

We are given an equation 2x - y = - 6.

We have to solve it.

The linear two-variable equation can be rearranged as y = 2x + 6 ........ (1)

Now, we need x values to get corresponding y values.{Since, there are two variables and only one equation}

It is given that the domain is (- 2, - 1, 0, 1).

Therefore, those are the x values for which we have to solve for y from equation (1).

For, x = - 2, y = 2( - 2 ) + 6 = 2 (Answer)

For, x = - 1, y = 2( - 1 ) + 6 = 4 (Answer)

For, x = 0, y = 2( 0 ) + 6 = 6 (Answer)

For, x = 1, y = 2( 1 ) + 6 = 8 (Answer)

3 0

3 years ago

What is the equation of the following line? Be sure to scroll down first to see all answer options. 10 (2, 10) (0, 0) - 10 10 2

sashaice [31]

to get the the equation of any straight line, we only need two points off of it, let's use the two points already in the picture.

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{2}}}\implies \cfrac{-10}{-2}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{5}(x-\stackrel{x_1}{2}) \\\\\\ y-10=5x-10\implies y=5x$

6 0

3 years ago