Answer: Radhika loves to eat sweets and chocolates. She asks her mother for the same before and after every meal. This is an example of bad eating habit.
Explanation:
Both sweets and chocolates contain high amount of fat and sugar. When Radhika is eating the same before and after every meal then it means she is consuming it in excess.
When we eat too much of sweets and chocolates then its remains get deposited in between our tooth and when they remain over there for hours then more amount of bacteria is formed.
Due to this bacteria our tooth starts to decay.
Hence, it is advised even by the doctors to eat sweets and chocolates occasionally and not regularly.
Thus, we can conclude that Radhika loves to eat sweets and chocolates. She asks her mother for the same before and after every meal. This is an example of bad eating habit.
Answer:
83ºC
Explanation:
A bomb calorimeter is an instrument used to measure the heat that release or absorb a particular reaction.
The reaction of combustion of propane is:
C₃H₈ + 5O₂ → 3 CO₂ + 4 H₂O ΔH = -2222kJ/mol
<em>1 mole of propane release 2222kJ</em>
10.0g of propane (Molar mass: 44.1g/mol).
10.0g ₓ (1mol/ 44.1g) = <em>0.227 moles of C₃H₈</em>
If 1 mole of propane release 2222kJ, 0.227moles will release (Release because molar heat is < 0):
0.227 moles of C₃H₈ ₓ (2222kJ / mol) = 504kJ.
Our calorimeter has a constant of 8.0kJ/ºC, that means if there are released 8.0kJ, the bomb calorimeter will increase its temperature in 1ºC. As there are released 504kJ:
504kJ ₓ (1ºC / 8.0kJ) = 63ºC will increase the temperature in the bomb calorimeter.
As initial temperature was 20ºC, final temperature will be:
<h2>83ºC</h2>
Answer:
Hi i got , B. He is right, because there will be more successful collisions between reactants in the 1.0 M solutions.
Explanation: Hope it helps !!
Answer:
Explanation:a cells state potential of the cell is the standard state conditions 1 mole per liter (1 m) and pressure of atmospheric 25oC
Answer:
3.27 x 10⁻¹⁶ grams
Explanation:
moles Au = 1.00 x 10⁻⁶ Atoms / 6.02 x 10²³Atoms / mole = 1.66 x 10⁻¹⁸ mole Au
grams Au = 1.66 x 10⁻¹⁸ mole Au x 196.97 grams Au/mole Au
= 3.27 x 10⁻¹⁶ grams Au
