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Lana71 [14]
3 years ago
11

A 10.0 g sample of propane, C3H8, was combusted in a constant-volume bomb calorimeter. The total heat capacity of the bomb calor

imeter and water was 8.0 kJ/°C. The molar heat of combustion of propane is -2 222 KJ/mol. If the starting temperature of the water was 20 °C, what will be the final temperature of the bomb calorimeter?
Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

83ºC

Explanation:

A bomb calorimeter is an instrument used to measure the heat that release or absorb a particular reaction.

The reaction of combustion of propane is:

C₃H₈ +  5O₂ → 3 CO₂ + 4 H₂O ΔH = -2222kJ/mol

<em>1 mole of propane release 2222kJ</em>

10.0g of propane (Molar mass: 44.1g/mol).

10.0g ₓ (1mol/ 44.1g) = <em>0.227 moles of C₃H₈</em>

If 1 mole of propane release 2222kJ, 0.227moles will release (Release because molar heat is < 0):

0.227 moles of C₃H₈ ₓ (2222kJ / mol) = 504kJ.

Our calorimeter has a constant of 8.0kJ/ºC, that means if there are released 8.0kJ, the bomb calorimeter will increase its temperature in 1ºC. As there are released 504kJ:

504kJ ₓ (1ºC / 8.0kJ) = 63ºC will increase the temperature in the bomb calorimeter.

As initial temperature was 20ºC, final temperature will be:

<h2>83ºC</h2>
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Steve walks from his house 5 I'm south then turns east and walks 2 km. Then he walks 9 in North to his older sister's house. She
IgorLugansk [536]

Answer:

18 km

Explanation:

To know the distance, you need to be clear in the concept of distance.

According to the physics, the distance is a measurement that refers to the fact of how much an object has move from one point to another.

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To calculate the distance that he moved, you just need to sum all the values of distance. In this case, it's not neccesary to do calculations regarding the components of the x or y axis, because we are not talking about displacement, where it actually counts. But in this case, we just need all the covered distance that Steven walked since the beggining.

So, no more talk, let's do calculations:

D = 5 + 2 + 9 + 2 = 18 km

So the final answer would be:

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Hope this helps

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A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
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Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g ×\frac{1mol}{159,609g} = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

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3 years ago
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