A drop of vinegar ( a weak acid ) is placed on a sample of each of the materials below. Which will show the most active reaction

Question

Anettt [7]

2 years ago

5

A drop of vinegar ( a weak acid ) is placed on a sample of each of the materials below. Which will show the most active reaction

?
A. glass
B. marble
C. copper
D. steel

Chemistry

2 answers:

professor190 [17] · Answer 1 · 2022-03-26T23:24:14+03:00

Answer: Option (B) is the correct answer.

Explanation:

Marble is also known as calcium carbonate and its chemical formula is $CaCO_{3}$ .

When it combines with vinegar then it results in the formation of calcium acetate which is a water soluble compound along with the release of carbon dioxide which occurs in the form of bubbles and water.

The reaction is as follows.

$CaCO_{3} + CH_{3}COOH \rightarrow Ca(CH_{3}COOH)_{2} + H_{2}O + CO_{2}$

Whereas vinegar being a weak acid will not react with glass, copper and steel.

ohaa [14] · Answer 2 · 2022-03-27T00:58:15+03:00

ohaa [14]2 years ago

5 0

Answer: B

Explanation: I got it right on my test

Brainliest?