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Anettt [7]
3 years ago
5

A drop of vinegar ( a weak acid ) is placed on a sample of each of the materials below. Which will show the most active reaction

?
A. glass
B. marble
C. copper
D. steel
Chemistry
2 answers:
professor190 [17]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

Marble is also known as calcium carbonate and its chemical formula is CaCO_{3}.

When it combines with vinegar then it results in the formation of calcium acetate which is a water soluble compound along with the release of carbon dioxide which occurs in the form of bubbles and water.

The reaction is as follows.

    CaCO_{3} + CH_{3}COOH \rightarrow Ca(CH_{3}COOH)_{2} + H_{2}O + CO_{2}

Whereas vinegar being a weak acid will not react with glass, copper and steel.

ohaa [14]3 years ago
5 0

Answer: B

Explanation: I got it right on my test

Brainliest?

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