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Ulleksa [173]
3 years ago
6

Suppose that you and a friend are playing cards and decide to make a bet. If your friend draws three non-face cards, where a fac

e card is a Jack, a Queen, or a King, in succession from a standard deck of 52 cards without replacement, you give him $10. Otherwise, he pays you $20. If the same bet was made 25 times, how much would you expect to win or lose? Round your answer to the nearest cent, if necessary.
Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0

First let us calculate the probability that three non-face cards will be drawn in succession without replacement.

There are 40 non-face cards in a deck of 52 cards.

Probability of 3 successive non-face cards = (40/52)*(39/51)*(38/50) = 0.447

Therefore, the probability that it will not be 3 successive non-face cards is 1-0.447 = 0.553

Hence, for each game the expected return would be:

Return = 0.447 * (-$10) + 0.553 ($20) = $6.59 per bet

For 25 bets:

Total return = $6.59 * 25

Total return = $164.75

If the bet is performed 25 times, expect to win $164.75.

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Hi there!

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We can begin by multiplying by its conjugate:

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Simplify using the identity:

1 - cos^2A = sin^2A

\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =

Take the square root of the expression:

{\frac{sinA}{1+cosA} =

Multiply again by the conjugate to get a SINGLE term in the denominator:

{\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\

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Use the above trig identity one more:

{\frac{sinA(1-cosA)}{sin^2A} =

Cancel out sinA:

{\frac{(1-cosA)}{sinA}  =

Split the fraction into two:

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Simplify:

\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}

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