Answer:
15, 8, 25 The teacher payed 0.40 per book.
Step-by-step explanation:
4/10 = 2/5 Simplify the 4/10 to find the unit rate.
15: 2/5 = 6/x Set up your proportion.
2x =30 Cross multiply
/2 /2 Divide both sides by 2 to isolate x
x =15
8: 2/5 = x/20 Set up proportion
40 =5x Cross multiply
/5 /5 Divide both sides by 5 to isolate x
8 =x
25: 2/5 = 10/x Set up proportion
2x =50 Cross multiply
/2 /2 Divide both sides by 2 to isolate x
x =25
Graph: y=mx+b To graph, you will need to use y=mx+b format
y= 2/5 x+2 2/5 is your unit rate. Your rate changes every 2 books bought. To graph, start at (0,2) and go up 2 and to the right 5, plot. Continue moving up 2 and to the right 5 to graph.
The teacher payed 0.40 per book because 2/5 simplifies to 0.40.
Answer:
The average rate of change is 
Step-by-step explanation:
The average rate of change from x=a to x=b of f(x) is given by;

We want to find the average rate of change of the function represented in the table from x=-2 to x=2.

From the table f(-2)=25 and f(2)=9
The average rate of change from x=-2 to x=2 is



★ Inequalities ★

or n ∈ ( 10 , 11 )
Possible value can be easily obtained by generating an arithmetic mean

Else we've infinite numbers between them ,
According to density property of real numbers , we can have any real number satisfying the given inequality under condition 10 < n < 11
Which is true for infinite possible numbers
10.1 , 10.2 , ... INFINITY
Answer/Step-by-step explanation:
To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.
Given, {2, 3, 5, 6, 10, 14, 15},
Minimum value = 2
Median = middle data point = 6
Q1 = 3 (the middle value of the lower part of the data set before the median)
Q3 = 14 (middle value of the upper part of the data set after the median)
Maximum value = 15
If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.
See the attachment below for the correct box plot.
Answer:
531.167 ft²
Step-by-step explanation:
Given data
Dimension of pool
Diameter =24ft
Radius =12ft
If the cover must hang by 1ft around, then the diameter is 26ft
Radius =13ft
Area of cover = πr²
Substitute
Area = 3.142*13²
Area =3.143*169
Area =531.167 ft²
Hence the minimum area is 531.167 ft²