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GalinKa [24]
3 years ago
8

5 ft is ____ % of 37 1 2 ft; 37 1 2 ft is ____ % of 5 ft

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

The answer is:

5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

Step-by-step explanation:

Given:

5 ft is ____ % of 37 1 2 ft.

Now, to find the __ :

Let __ be x.

So, 5 ft is x\% of 37 1/2

5=x\% of 37\frac{1}{2}

⇒ 5=\frac{x}{100} \times \frac{75}{2}

⇒ 5=\frac{75x}{200}

Multiplying both sides by 200 we get:

⇒ 1000=75x

Dividing both sides by 75 we get:

⇒ 13.33=x

⇒ x=13.33\%.

Now, 37 1/2 ft is x% of 5 ft.

\frac{75}{2} =x\%\ of\ 5

\frac{75}{2}=\frac{x}{100}\times 5

\frac{75}{2} =\frac{5x}{100}

Multiplying both sides by 100 we get:

\frac{7500}{2} =5x

Dividing both sides by 5 we get:

750=x

x=750\%

Therefore, the answer is 5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

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4 years ago
Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

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2 years ago
Hey guys can you help me pls
hjlf

Answer:

the top is 16/4

Step-by-step explanation:

6 0
3 years ago
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