The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer: 2/15
Step-by-step explanation:
25-21/30 = 4/30
4/30 = 2/15
Answer:
<em>Beck actually caught 45 fish</em>
Step-by-step explanation:
<u>System of Equations</u>
We call the following variables:
x = number of fish Ally caught
y = number of fish Beck caught
They caught a total of 75 fish, thus:
x + y = 75 [1]
If Ally had caught twice as much fish as she actually did, and Beck had caught three times as many fish as he actually did, then Ally would have caught 75 fewer fish than Beck, thus:
3y = 2x + 75 [2]
From [1]:
x = 75 - y [3]
Substituting in [2]:
3y = 2(75 - y) + 75
Operating:
3y = 150 - 2y + 75
Simplifying:
5y = 225
Dividing by 5:
y = 45
Beck actually caught 45 fish
Answer:
rate of change = 1.5 dollars per mile
Step-by-step explanation:
cost for travelling 1 mile = 3.75
cost 2 miles = 5.25
cost 3 miles = 6.75
cost 4 miles = 8.25
132 or 2.304 radian ? still not really sure what's being asked
