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Simora [160]
3 years ago
11

What are the solutions of the quadratic equation (x + 3)2 = 49? A. O x = 2 and x = - 10 B.O.x = 4 and x = -10 C.O x=-2 and x = -

16 D.O x = 40 and x = -58​
Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

B. x = 4 and x = -10

Step-by-step explanation:

First, expand the equation

(x + 3)² = 49

(x + 3)(x + 3) = 49

x² + 6x + 9 = 49

Subtract 49 from both sides

x² + 6x -40 = 0

Factor

(x + 10)(x - 4) = 0

Solve

x + 10 = 0

x = -10

x - 4 = 0

x = 4

So, the correct answer is B. x = 4 and x = -10

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zheka24 [161]

Answer:

6x+6+\frac{5}{x+5}

Step-by-step explanation:

When we divide polynomials by polynomials with more than one term, we use long division or factorization to simplify.

This polynomial isn't easily divided after factorization so we will use long division. And we will use the remainder theorem to write any remainder.

\frac{(6x^2+36x+35)}{(x+5)}

We start long division by finding what multiplies with x+5 to get  6x^2+36x. This is 6x.

So 6x(x+5)=6x^2+30x. We have 6x left as a remainder from 36x.

We now divide x+5 into 6x+35. What multiplies with x+5 to get 6x+35? 6.

So we have 6x+6 as our answer so far and after we multiply 6(x+5)=6x+30 we will have a final remainder of 5.

We write our answer as 6x+6+\frac{5}{x+5}.


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