Answer:
domain: 2x+1 not equal to zero, then x not equal to -1/2
Set 2x+1>0
then x>-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)<=0.01^(5x-8)
(10^2)^(3-4x)<=[10^(-2)]^(5x-8)
10^[2*(3-4x)]<=10^[(-2)*(5x-8)]
10^(6-8x)<=10^(16-10x)
6-8x<=16-10x
2x<=10
x<=5
combine x>-1/2 and x<=5
then - 1/2<x<=5
Set 2x+1<0
then x<-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)>=0.01^(5x-8)
(10^2)^(3-4x)>=[10^(-2)]^(5x-8)
10^[2*(3-4x)]>=10^[(-2)*(5x-8)]
10^(6-8x)>=10^(16-10x)
6-8x>=16-10x
2x>=10
x>=5
combine x<-1/2 and x>=5
, then x does not exist while 2x+1<0
so answer is - 1/2<x<=5
Let x be the amount of weeks.
60 + 7x = 120
60 - 60 + 7x = 120 - 60
7/7x = 60/7
x = 8.571428571
Answer:
10.8 gallons
Step-by-step explanation:
First change everything to inches:
2.75 ft = 33 in
1.5 ft = 18 in
Volume of tank = lwh = (33)(18)(7) = 4158 in³
The tank is 40% full, so only 60% is need to fill it. To find 60%, multiply 4158 by 0.6 = 2494.8 in³
Now find out how much 2494.8 in³ is in gallons:
231 in³ = 1 gallon
1 in³ = 1/231 gallons
2494.8 = (1/231)(2494.8) gallons = 10.8 gallons
The equation of the line of best fit is y = 1.7x - 58
<h3>How to determine the equation?</h3>
We start by drawing the line of best fit (see attachment)
From the attached graph, we have the following points
(x, y) = (70, 75) and (61, 60)
The slope (m) is:
m = (y2 - y1)/(x2 - x1)
This gives
m = (60 - 75)/(61 - 70)
Evaluate
m = 1.7
The line of best fit is then calculated as:
y = m(x - x1) + y1
This gives
y = 1.7(x - 70) + 61
This gives
y = 1.7x - 119 + 61
Evaluate
y = 1.7x - 58
Hence, the equation of the line of best fit is y = 1.7x - 58
Read more about line of best fit at:
brainly.com/question/14279419
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